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Gnom [1K]
3 years ago
13

Find the 1. rang 2. domain 3. intervals where the graph is positive

Mathematics
1 answer:
liberstina [14]3 years ago
5 0
Hey y’all I don’t know how rang
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*PLEASE ANSWERRR!!! NEED HELP ASAP*
adoni [48]

Answer:

The Mean is increased by 2.

Step-by-step explanation:

Mark brainliest please good luck with that test ;)

6 0
3 years ago
Hi I need help with this question
katrin2010 [14]
This is the answer to the problem. You basically substitute the -6 in for the f(x)

5 0
3 years ago
Read 2 more answers
Perform the indicated operation. x/2+y/3-z/4
weeeeeb [17]

\bf \cfrac{x}{2}+\cfrac{y}{3}-\cfrac{z}{4}\implies \stackrel{\textit{using the LCD of 12}}{\cfrac{(6)x~~+~~(4)y~~-~~(3)z}{12}}\implies \cfrac{6x+4y-3z}{12}

3 0
4 years ago
Read 2 more answers
4x/x+3 - 4x/x+6 <br> Please help me find the right answer thxs
Arisa [49]

Answer:

9

Step-by-step explanation:

For 4x/x+3, just cancel the x to get 4+3=7

For -4x/x+6, cancel the x to get -4+6=2

7+2=9

Hope this helps

6 0
4 years ago
Find an equation of the tangent line to the curve 2(x2+y2)2=25(x2−y2) (a lemniscate) at the point (−3,1). An equation of the tan
valina [46]

2(x^2+y^2)^2=25(x^2-y^2)

Let y=y(x), so that differentiating both sides wrt x gives

4(x^2+y^2)\left(2x+2y\dfrac{\mathrm dy}{\mathrm dx}\right)=25\left(2x-2y\dfrac{\mathrm dy}{\mathrm dx}\right)

If x=-3 and y=1, the above reduces to

40\left(-6+2\dfrac{\mathrm dy}{\mathrm dx}\right)=25\left(-6-2\dfrac{\mathrm dy}{\mathrm dx}\right)\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac9{13}

This is the slope of the tangent line, which has equation

y-1=\dfrac9{13}(x+3)\implies\boxed{y=\dfrac{9x+40}{13}}

7 0
3 years ago
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