3 years ago

Hi I need help with this question

Mathematics

2 answers:

Fittoniya [83]3 years ago

6 0

What they said ^^^ :)

katrin2010 [14]3 years ago

5 0

This is the answer to the problem. You basically substitute the -6 in for the f(x)

You might be interested in

All numbers are divisible by

qwelly [4]

Answer:

one

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A study of 2500 randomly selected students of a major university showed that 300 students tried to turn in work late to at least

dsp73

Answer:

Step-by-step explanation:

4 0

3 years ago

What place does the 3 have in 8.3

Ghella [55]

The 3 is in the tenths place

3 0

3 years ago

Read 2 more answers

A square is a quadrilateral always sometimes never

lbvjy [14]

A quadrilateral is a shape with 4 sides, regardless of their lengths, angles, or symmetry.

Therefore, a square is always a quadrilateral.

6 0

3 years ago

Read 2 more answers

Fundamental theorem of calculus<br> <img src="https://tex.z-dn.net/?f=g%28s%29%3D%5Cint%5Climits%5Es_6%20%7B%28t-t%5E4%29%5E6%7D

mr_godi [17]

Answer:

$\displaystyle g'(s) = (s-s^4)^6$

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
$\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt \right] = f(x)$

Where <em>a</em> is some constant.

We can let:
$\displaystyle g(t) = (t-t^4)^6$

By substitution:

$\displaystyle g(s) = \int_6^s g(t)\, dt$

Taking the derivative of both sides results in:
$\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]$

Hence, by the Fundamental Theorem:

$\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\ & = (s-s^4)^6\end{aligned}$

3 0

2 years ago