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Leya [2.2K]
3 years ago
12

Hi I need help with this question

Mathematics
2 answers:
Fittoniya [83]3 years ago
6 0
What they said ^^^ :)
katrin2010 [14]3 years ago
5 0
This is the answer to the problem. You basically substitute the -6 in for the f(x)

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12/15=x/10 solve for x
Alexandra [31]

Answer: x=8

Step-by-step explanation:

This is a simple cross multiplication problem:

12/15=x/10

=> 15x=120

=> x=8

There is your answer.

Have a nice day! :)

7 0
3 years ago
Read 2 more answers
Whats the answer for (5x + 8)(4x² + 6x - 8)
mestny [16]
(5x + 8)(4x^2 + 6x - 8)\\ \\ 5x(4x^2 + 6x - 8) + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 32x^2 + 48x - 64 \\ \\ 20x^3 + (30x^2 + 32x^2) + (-40x + 48x) - 64 \\ \\ 20x^3 + 62x^2 + 8x - 64 \\ \\

The final result is: 20x^3 + 62x^2 + 8x - 64.
4 0
3 years ago
Suppose a pack of candy bars has 4 bars. Each bar weighs 5.88 ounces. How much does the pack weigh?
frutty [35]
The answer is 23.52 the keyword is each so you multiply.
7 0
3 years ago
Read 2 more answers
Two automobiles start together from the same place and travel along the same route. The first averages 40 miles
natita [175]

Answer:

A. (55 x 5) - (40 x 5)

Step-by-step explanation:

You are solving how much miles (further along) would the second car be after 5 hours.

The first car averages 40 miles per hour. 5 hours later, it will have averaged about 200 miles in 5 hours (40 x 5 = 200).

The second car averages 55 miles per hour. 5 hours later, it will have averaged about 275 miles in 5 hours (55 x 5 = 275)

Subtract: 275 - 200 = 75

The second car would have averaged 75 more miles than the first car.

~

4 0
3 years ago
Read 2 more answers
I need help please.
Rainbow [258]
The answer should be C
54*30/100= 16.2
54-16.2 = 37.80
4 0
3 years ago
Read 2 more answers
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