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kipiarov [429]
3 years ago
13

The matrix is used to solve a problem. Which of the following would be a solution to the problem?

Mathematics
2 answers:
Liula [17]3 years ago
5 0

Answer:

(1,5)

Step-by-step explanation:

Hope this is right.

Ierofanga [76]3 years ago
5 0

Answer:

It's (1,0)

Step-by-step explanation:

I got it right on the quiz

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Please help, I don't understand.. <br><br>Thanks!​
olga nikolaevna [1]

Answer:

$109.45

Step-by-step explanation:

On Monday in the morning you worked 4 hours, so plug in the equation.

12.50(4)= $50

On Monday in the afternoon you worked 4 hours and 45 min

12.50(4) = $50

Then do 12.50/60 to get .208 ≈ .21

So 45(.21) = $9.45

50 +50 + 9.45= 109.45

6 0
3 years ago
What is seven hundred twelve thousandths in expanded form?
elena-14-01-66 [18.8K]
I'm pretty sure the answer is
.700 + .12
3 0
3 years ago
Read 2 more answers
I need help with 6 a) and all of 7 :)
attashe74 [19]
6 a)
((10+2)•3^2 ) -2= 12•9-2=108-2=106
4 0
4 years ago
Read 2 more answers
I need to solve this using l'hopital's rule and logarithmic diferentiation.
arlik [135]

Yo sup??

For our convenience let h=x+1

therefore

when x tends to -1, h tends to 0

hence we can rewrite it as

\lim_{h \to \ 0 } (cos(h))^{(cot(h^2 )}

This inequality is of the form 1∞

We will now apply the formula

e^(^g^(^x^)^(^f^(^x^)^-^1^)^)

plugging in the values of g(x) and f(x)

e^{lim_{h \to \ 0}{(cot(h)^2(cos(h)-1))}

express coth² as cosh²/sinh² and also write cosh-1 as 2sin²(h/2)

(by applying the property that cos2x=1-sin²x)

After this multiply the numerator and denominator with h² so that we can apply the property that

\lim_{x \to \ 0 } sinx/x =1

Now your equation will look like this.

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2)*h^2)/(sin(h)^2*h^2)}

We will now apply the result

\lim_{x \to \ 0 } sinx/x =1

where x=h²

we get

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2))/(h^2)}

we now multiply the numerator and denominator with 4 so that we can say

\lim_{h^2 \to \ 0 } sin^2(h/2)/(h^2/4) = 1

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2))/(h^2*4/4)}

=e^{lim_{h \to \ 0}{((cos(h)^2*2)/(4)}

Apply the limits and you will get

e^{cos(0)^2*2/4

=e^{1/2}

Hope this helps.

7 0
3 years ago
12. Find the value of x.
Ivanshal [37]
6 is the value of x in this
5 0
4 years ago
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