Hello,
A: True (4 sides equals in a square)
B: True all rectangle has a symetry centre
C: True (2 sides // in a rhombuse since is a parallelogram)
D:False
First, illustrate the problem into a diagram like the one shown in the attached picture. The component vectors are shown in red (y-component) and blue (x-component). Since this is a right triangle, let's apply the trigonometric functions of sine and cos.
y-component, vy:
sin (π/3) = vy/8
vy = 6.928x-component, vx:
cos (π/3) = vx/8
vx = 4
The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
Answer:
<u>The Answer in Exact Form:</u>
-3/22
<u>In Decimal Form:</u>
-0.136
Step-by-step explanation:
-
÷5
=-3/22
Answer:
1. 10
2. 35
3. amelia
4. 5
this is using only the graph and not the text provided above. hopefully the graph is right :P
