The set of ordered pairs represents a function. Write a rule that represents the function.
1 answer:
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We are told that circle C has center (-4, 6) and a radius of 2.
We are told that circle D has center (6, -2) and a radius of 4.
If we move circle C's center ten units to the right and eight units down, the new center would be at (-4 + 10), (6 - 8) = (6, -2). So step 1 in the informal proof checks out - the centers are the same (which is the definition of concentric) and the shifts are right.
Let's look at our circles. Circle C has a radius of 2 and is inside circle D, whose radius is 4. Between Circle C and Circle D, the radii have a 1:2 ratio, as seen below:
If we dilate circle C by a factor of 2, it means we are expanding it and doubling it. Our circle has that 1:2 ratio, and doubling both sides gives us 2:4. The second step checks out.
Translated objects (or those that you shift) can be congruent, and dilated objects are used with similarity (where you stretch and squeeze). The third step checks out.
Thus, the argument is correct and the last choice is best.
Answer:
So the solution set of the equations are {(-1,4)}
or
the solution is x = -1 and y = 4
Step-by-step explanation:
Equations given to us are
y = -3x + 1 ..................(i)
2x + 5y = 18 .................(ii)
To find the value of x and y or the solution set of the system of equations
Now in first equation we see that
y = -3x + 1
Putting this value in equation (ii)
which is
2x + 5y = 18
Putting value of y from (i) in it
2x + 5(-3x + 1) = 18
Opening the bracket and multiplying inside
2x -15x + 5 = 18
-13 x + 5 = 18
Subtracting 5 from both sides of the equation
-13x + 5 - 5 = 18 -5
-13x = 13
Dividing both sides by -13
Cutting out the same values gives us
x = -1
For value of y
putting value of x in equation (i)
which is
y = -3x + 1
Putting the value
y = -3(-1)+1
y=3+1
y=4
So the solution set of the equations are {(-1,4)}
or
the solution is x = -1 and y = 4
Answer and Step-by-step explanation:
I will be using Desmos to show you the graph.
So, draw your line from the equation, and then lightly shade the left and ride side. That middle side is where there is no solutions for -3 ≤ x ≤ -5 for y = 2x - 5.
The parts that are shaded have the solutions.
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