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Over [174]
3 years ago
9

Tính kết quả \sqrt[3]{1}

Mathematics
1 answer:
vitfil [10]3 years ago
6 0

Answer:

ano po yung question hindi kupo maintindihan pano kupo sa sagutan

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HELP HELP ASAP!!!!!!!!!!!!!!!!!!!!
Keith_Richards [23]

Answer:

You don't need help you got this

Step-by-step explanation:

no you don't got this now do your work and stop reading this bye :)

5 0
3 years ago
a house has a rectangular tile kitchen that is 7 tiles wide and 8 tiles long. It also has a rectangular dining room that is 9 ti
Eduardwww [97]
7*8 = 56
9*10 = 90 add them
ANSWER = 146 tiles
7 0
3 years ago
Which expression can be substituted for x in the top equation of the following system to solve the system by substitution? 2x−7y
Ivanshal [37]
From the second equation:-
x = 6 - 4y
Substitute this for x in the top equation
6 0
3 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
Norma-Jean [14]

The positions when the particle reverses direction are:

s(t_1)=55ft\\\\s(t_2)=28ft

The acceleraton of the paticle when reverses direction is:

a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

s(t)=2t^{3}-21t^{2}+60t+3

So,

- Derivating to get the velocity function, we have:

v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42

Now, substituting the times to calculate the accelerations, we have:

a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}

Now, substitutitng the times to calculate the positions, we have:

s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft

Have a nice day!

3 0
3 years ago
4. The following intervals were plausible population proportions for a given sample. Find the margin of error in each case.
Vedmedyk [2.9K]

Answer: a. 0.15  b. 0.03 c. 0.055 d. 0.05

Step-by-step explanation:

For plausible intervals of population proportions , the margin of error is basically half of the difference between upper limit and lower limit.

a.  Interval =  From 0.35 to 0.65

Upper limit = 0.65

Lower limit = 0.35

Difference = Upper limit- Lower limit

= 0.65-0.35=0.30

Margin of error = (Difference)÷2  =(0.30)÷2=0.15

b. Interval =  From 0.72 to 0.78

Upper limit = 0.78

Lower limit = 0.72

Difference =  0.78-0.72 = 0.06

Margin of error  =(0.06)÷2=0.03

c. Interval =  From 0.84 to 0.95

Upper limit = 0.95

Lower limit = 0.84

Difference =0.95-0.84= 0.11

Margin of error = (0.11)÷2 = 0.055

d.Interval =  From 0.47 to 0.57

Upper limit =  0.57

Lower limit =  0.47

Difference = 0.57-0.47=0.10

Margin of error = (0.10)÷2=0.05

3 0
4 years ago
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