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lesya692 [45]
3 years ago
11

I will give brainliest please help

Mathematics
2 answers:
zimovet [89]3 years ago
5 0

Answer:

x^5y^5

Step-by-step explanation:

<em>here's</em><em> your</em><em> solution</em>

=> if base are same then power get added in multiplication

=> so, x^2 * y^4 * x^3 * y^1

=> x^2 * x^3 * y^4 * y^1

=> x^5*y^5

hope it helps

kakasveta [241]3 years ago
5 0
X^5,y^5 because you add the two and three and get five so it’ll be x to the fifth power then you add four and one but there isn’t a number on the y at the end so that automatically makes it one so add four and one you get five so therefore the answer is x^5,y^5
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Answer:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

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Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

Step-by-step explanation:

Information given

\bar X=1.8 represent the sample mean for the growth

s=0.5 represent the sample standard deviation    

n=48 sample size    

\mu_o =2 represent the value that we want to compare

\alpha=0.01 represent the significance level

t would represent the statistic    

p_v represent the p value

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 2cm per week, the system of hypothesis are :    

Null hypothesis:\mu \geq 2    

Alternative hypothesis:\mu < 2    

Since we don't know the population deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing the info given we got:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

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