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Umnica [9.8K]
3 years ago
11

How do you find the x and y intercepts from a table

Mathematics
1 answer:
Ronch [10]3 years ago
7 0
The first step is to find the slope which is (y2-y1)/(x2-x1) and you can use any of these points. Next write the equation is point slope form which is y-y1=m(x-x1) using the slope and one of the points. Then you can simplify to write this is slope-intercept form and solve the x and y intercepts as given.
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Two groups of hikers leave the same camp heading in opposite directions. The first group travels 4 miles north and 3 miles east.
SCORPION-xisa [38]

Answer:

The first groups travels 7 miles total, and the second group travels 7 miles in total also

Step-by-step explanation:

They are completely equal

5 0
3 years ago
What is the correct 3 syllables on this words, decorate, temperature, equation, vertical?
Rzqust [24]
If you're asking what I think you are, 
Decorate, Equation, and Vertical has 3 syllables.
Temperature has 4 syllables - <span>tem-per-a-ture</span>
3 0
3 years ago
There are 3/4 as many boys as girls in a class of fifth graders. If there are 35 students in the class, how many are girls?
OLEGan [10]

Answer:

20 There are 15 boys and 20 girls.

4 0
3 years ago
Find the slope of the line segment that joints the points A(2, -8) and B(-1, 16)
Karo-lina-s [1.5K]
We need to use the Point slope formula to find the slope so we label
(2 , -8);(-1 , 16) subtract
x1 y1 x2 y2. y2-y1/x2-x1
16-(-8)/-1-2 = 24/-3 = -8
meaning the slope of this line is (-8)
8 0
3 years ago
Kind people!help me please...And a detailed solution/THANKS<br> sin^2x-0,5sin2x=0
Volgvan

This will be easier to write, and a lot easier to read, if we temporarily
use another symbol ... say, 'Q' ... to represent  ' sin(2x) ' .
Here we go:

Original equation:                Q² - 0.5 Q  =  0

Factor the left side:            Q (Q - 0.5)  =  0

This equation is true if either factor is zero:


--  If  Q=0, then  sin(2x) = 0

                                 2x = 0°,  180°,  360°

                                   x = 0°,  90°,  180°


-- If  (Q-0.5) = 0, then      Q  =  0.5

                                sin(2x)  =  0.5          

                                       2x  =  30°,  150°

                                         x  =  15°,  75°


The whole collection of solutions
between  0°  and  360° :

          x = 0°,  15°,  75°,  90°,  180° .

8 0
3 years ago
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