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3 years ago

Please show your work. i’ll give brainliest!

Mathematics

2 answers:

Orlov [11]3 years ago

8 0

A coefficient is a number that is being multiplied by a variable. In this case, we see that x in one term is being multiplied by 4, and in another term, x is being multiplied by -16 (If you change the operation to addition, you negate the 16).

So the coefficients in this expression are: 4 and -16.

pshichka [43]3 years ago

6 0

Factor 4x2−16x+16

4x2−16x+16

=4(x−2)(x−2)

Answer:

4(x−2)(x−2)

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Which unit would be most appropriate to measure the

Effectus [21]

Answer:

measure the length of the area.and the width of the area. using feet

5 0

3 years ago

Two quadratic functions are shown.

slava [35]

Answer:

Option (1) is the correct option.

Step-by-step explanation:

Function 1,

f(x) = 4x² + 8x + 1

= 4(x² + 2x) + 1

= 4(x² + 2x + 1 - 1) + 1

= 4(x² + 2x + 1) - 4 + 1

f(x) = 4(x + 1)² - 3

This graph opens up with the vertex or minimum point at (-1, -3)

So, the minimum value of the function is (-3) at x = -1.

Function (2)

From the given table minimum value of the function is 0 at x = -1 or minimum point as (-1, 0)

Therefore, Function 1 has the least minimum value and its coordinates are (-1, -3)

Option (1) is the correct option.

7 0

3 years ago

If g(x) = -2x - 2, find g(-2x).

USPshnik [31]

Answer:

Step-by-step explanation:

You would replace the x with -2x so you would end up with -2×-2 and that is 4 then minus 2 is 2.

7 0

3 years ago

What’s the vertex form of F(x)=x^2+2x-3

kupik [55]

Answer:

$\large\boxed{f(x)=(x+1)^2-4}$

Step-by-step explanation:

$\text{The vertex form of a quadratic equation}\ f(x)=ax^2+bx+c:\\\\f(x)=a(x-h)^2+k\\\\(h,\ k)-\text{vertex}\\=====================================$

$\bold{METHOD\ 1:}\\\\\text{convert to the perfect square}\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\f(x)=x^2+2x-3=\underbrace{x^2+2(x)(1)+1^2}_{(*)}-1^2-3\\\\f(x)=(x+1)^2-4\\==============================$

$\bold{METHOD\ 2:}\\\\\text{Use the formulas:}\ h=\dfrac{-b}{2a},\ k=f(k)\\\\f(x)=x^2+2x-3\to a=1,\ b=2,\ c=-3\\\\h=\dfrac{-2}{2(1)}=\dfrac{-2}{2}=-1\\\\k=f(-1)=(-1)^2+2(-1)-3=1-2-3=-4\\\\f(x)=(x-(-1))^2-4=(x+1)^2-4$

4 0

3 years ago

I need help with pythagoras’ theorem

fomenos

Answer:

Pythagoras’ theorem is a way to find a side or hypothesis when you have 2 sides.

The formula is: a^2 + b^2 = c^2

a and b are sides

c is the hypothesis

<u>Ex: A triangle has a leg that is 5 inches and a leg that is 7 inches. Find the hypothesis using Pythagoras' theorem. </u>

A leg is another way of saying a side.

5^2 + 7^2 = c^2

25 + 49 = x^2

sqrt(74) = sqrt(x^2)

sqrt(74) inches = hypothesis

<u>Ex: A triangle has a leg that is 9 feet and a hypothesis that is 25 feet. Find the other leg using Pythagoras' theorem. </u>

9^2 + b^2 = 25^2

81 + b^2 - 81 = 625 - 81

sqrt(b^2) = sqrt(544)

b = sqrt(554)

Do you understand more?

4 0

3 years ago