P needs to be something that is multiplied through 5-2n to equal 5/6-1/3n. Since you see that there is a 5 of somesort in both equations an easy place to start is simply making p=1/6. Once you do that then 5*1/6=5/6 so the first part is okay. Then 2n*1/6=2n/6 which is able to be reduced to n/3.
Based on this it is clear that p should equal 1/6.
Let x% be the salt concentration of first solution.
Then in 8ml, amount of salt = ![\frac{8x}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B8x%7D%7B100%7D)
Given that to this 8ml solution, 11ml solution of a 47% salt solution is mixed.
amount of salt in 11ml of 47% salt solution is
= ![\frac{517}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B517%7D%7B100%7D)
So, total amount of salt in new mixture = ![\frac{8x}{100} +\frac{517}{100} = \frac{8x+517}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B8x%7D%7B100%7D%20%2B%5Cfrac%7B517%7D%7B100%7D%20%3D%20%5Cfrac%7B8x%2B517%7D%7B100%7D)
But given that this new solution is a 43% salt solution.
Hence amount of salt in new mixture of (8+11)=19ml solution of 43% salt solution is ![\frac{19*43}{100} = \frac{817}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B19%2A43%7D%7B100%7D%20%3D%20%5Cfrac%7B817%7D%7B100%7D)
Hence ![\frac{8x+517}{100} = \frac{817}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B8x%2B517%7D%7B100%7D%20%3D%20%5Cfrac%7B817%7D%7B100%7D)
8x+517 = 817
8x=817-517 = 300
x= 300/8 = 37.5
Hence the salt concentration in the first solution is 37.5%
Answer: The height of the tree is 64.94ft
Step-by-step explanation:
Using the trigonometry of angles
Tan theta = opposite/adjacent
Tan 33° = height of the tree/100
Height of the tree= tan 33° * 100
= 0.6494*100
= 64.94ft
The height of the tree is 64.94ft
Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) .
Rule: (x, y)→(x + 8, y + 1 )
J’ (-2, 2) → (-2 + 8, 2 + 1 ) → (6, 3 )
K’ (-3, -4) → (-3 + 8, -4 + 1 ) → (5, -3 )
L’ (1, -2) → (1 + 8, -2 + 1 ) → (9, -1)
J’ (6,3)
K’ (5,-3)
L’ (9,-1)
Hope this helps!
Answer:
x=−2
Step-by-step explanation:
−2x+5−5=9−5
−2x=4
-2x/-2 = 4/-2
x=−2