Answer:
the desiner shpuld exept it
Step-by-step explanation:
Answer:
y=6x+20
Step-by-step explanation:
Answer:
C = (7, 6)
Step-by-step explanation:
The problem statement tells us the relation between the points is ...
(B-A)/(C-A) = 2/7
7(B -A) = 2(C -A) . . . . . . multiply by 7(C-A)
7B -7A +2A = 2C . . . . . add 2A
C = (7B -5A)/2 . . . . . . . divide by 2
C = (7(2, -4) -5(0, -8))/2 = (14, 12)/2 . . . . . fill in the values of A and B
C = (7, 6)
Answer:
Elimination isn't exactly the easiest for this situation. But since the equations are in the same form and not solved for the same variable, I would go with elimination. (If they were solved for the same variable, I would go with substitution.) It would require me to make a manipulation on both equations.
I would multiply first equation by 5 and second equation by -2. The reason I would do this is because the y's would have opposite coefficients and when you add opposites you get 0.
The new set of equations would look like this:
20x+10y=45
-14x-10y=2
But I will slope here since we aren't asked to solve it.
Some texts use the term linear combination instead of elimination. They are the same.