All categories

3 years ago

Can someone help with this?

Mathematics

1 answer:

Nady [450]3 years ago

3 0

Answer:

a) General admission since it costs 45 dollars total and the vip costs 50 dollars

b) VIP, since for the vip it's 15 rides for 80$ and 12 rides for the general, the vip is generally for the people who want to go on more rides compared to the general

Step-by-step explanation:

You might be interested in

In Miami the number of highway accidents increased by 20% over a four year period. How many accidents were there in 2013 if ther

wariber [46]

X/5120=20/100
x/5120=1/5
5120/5=1024
1024+5120=6144
6144 is the answer.

9 0

3 years ago

What number is between 0-5

svet-max [94.6K]

Answer:

The numbers are 0 12345

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Solve for X Cosine 59 degree angle the adjacent is 16

andre [41]

Answer:

Step-by-step explanation:

J we be w e e e e d. D

7 0

2 years ago

16. A proportional relationship between the number of pounds of tomatoes (x) and the price in dollars (y) is graphed, and the or

kondaur [170]

The relationship being proportional means there is a value of k such that

... y = k·x

We are given the point (6 (pounds), 3 (dollars)), so we can write ...

... 3 dollars = k·6 pounds

Dividing by 6 pounds, we get

... (3/6) dollars/pound = k = $0.50/lb

Now, we can use x=1 pound to find the price (y),

... y = ($0.50/lb)·(1 lb)

... y = $0.50 . . . . the price of 1 pound of tomatoes.

4 0

3 years ago

Find the multiplicative inverse of 3 − 2i. Verify that your solution is corect by confirming that the product of

leonid [27]

Answer:

$\frac{3}{13} + \frac{2i}{13}$

Step-by-step explanation:

The multiplicative inverse of a complex number y is the complex number z such that (y)(z) = 1

So for this problem we need to find a number z such that

(3 - 2i) ( z ) = 1

If we take z = $\frac{1}{3-2i}$

We have that

$(3- 2i)\frac{1}{3-2i} = 1$ would be the multiplicative inverse of 3 - 2i

But remember that 2i = √-2 so we can rationalize the denominator of this complex number

$\frac{1}{3-2i } (\frac{3+2i}{3+2i } )=\frac{3+2i}{9-(4i^{2} )} =\frac{3+2i}{9-4(-1)} =\frac{3+2i}{13}$

Thus, the multiplicative inverse would be $\frac{3}{13} + \frac{2i}{13}$

The problem asks us to verify this by multiplying both numbers to see that the answer is 1:

Let's multiplicate this number by 3 - 2i to confirm:

$(3-2i)(\frac{3+2i}{13}) = \frac{9-4i^{2} }{13} =\frac{9-4(-1)}{13}= \frac{9+4}{13} = \frac{13}{13}= 1$

Thus, the number we found is indeed the multiplicative inverse of 3 - 2i

4 0

3 years ago