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ASHA 777 [7]
3 years ago
11

Which line is perpendicular to the line whose equation is 5y + 6 = -3x?

Mathematics
1 answer:
Lynna [10]3 years ago
6 0

Answer: B

Step by Step

5y + 6 = -3X

5y = -3X - 6

Y = -3/5X -6/5

Perpedicular is the flip of your slope so -3/5 becomes 5/3X

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the length of a rectangle is 2ft more than twice the width. The area is 180 ft^2. find the length and width of the rectangle
Mariana [72]

Answer:

Area = length * width

 

112 = (2w+2)*w

 

112 = 2w^2 + 2w

 

0 =2w^2 + 2w - 112

 

0 = w^2 + w - 56

 

0 = (  w  +  8  )( w  -    7  )

 

w+8=0  results in negative measures

 

w-7=0 --> w = 7

 

width is 7

length is 16

3 0
2 years ago
Can someone help me plz ​
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4 0
3 years ago
Please I need help step by step
zaharov [31]
To find the surface area, you need to do the following:
A side of the figure is a trapezoid, so you should do 13+5x7 (since there are 2 of the same sides there is no need to divide by two.) and it should equal 126. To find the area of the top of the figure, you need to do 5x2 which equals 10. The area of the bottom of the figure is 26 (13x2), then do 2x3x2 to get the sides on the left and right of the figure. After all of this, add them together. (126+10+26+12=174.)
The surface area should be 174mm.
6 0
3 years ago
Find the value of X. Please show work.
OverLord2011 [107]

Answer:

x=11.2

Step-by-step explanation:

8 0
3 years ago
Find the inverse of the following function. Then prove they are inverses of one another.
solmaris [256]

Answer: \dfrac{x^2+1}{2}

Step-by-step explanation:

Given

f(x)=\sqrt{2x-1}

We can write it as

\Rightarrow y=\sqrt{2x-1}

Express x in terms of y

\Rightarrow y^2=2x-1\\\\\Rightarrow x=\dfrac{y^2+1}{2}

Replace y be x to get the inverse

\Rightarrow f^{-1}(x)=\dfrac{x^2+1}{2}

To prove, it is inverse of f(x). f(f^{-1}(x))=x

\Rightarrow f(f^{-1}(x))=\sqrt{2\times \dfrac{x^2+1}{2}-1}\\\\\Rightarrow f(f^{-1}(x))=\sqrt{x^2+1-1}\\\\\Rightarrow f(f^{-1}(x))=x

So, they are inverse of each other.

8 0
3 years ago
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