The area of the small poster is 160 inches square
<h3>How to determine the area</h3>
From the information given, we have the poster to take the form of a rectangle
The formula for area of a rectangle is;
Area = length × width
For the smaller poster created using a scale of factor 2/3
Length = 2/ 3 × 24
Length = 16 inches
Width = 2/ 3 × 15
Width = 10 inches
Substitute into the formula
Area = 16 × 10
Area = 160 inches square
Thus, the area of the small poster is 160 inches square
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Answer:
(3 x + 5) (x + 5)
Step-by-step explanation:
Factor the following:
3 x^2 + 20 x + 25
Hint: | Factor 3 x^2 + 20 x + 25 by finding factors of 3×25 whose sum is 20.
Factor the quadratic 3 x^2 + 20 x + 25. The coefficient of x^2 is 3 and the constant term is 25. The product of 3 and 25 is 75. The factors of 75 which sum to 20 are 5 and 15. So 3 x^2 + 20 x + 25 = 3 x^2 + 15 x + 5 x + 25 = 5 (3 x + 5) + x (3 x + 5):
5 (3 x + 5) + x (3 x + 5)
Hint: | Factor common terms from 5 (3 x + 5) + x (3 x + 5).
Factor 3 x + 5 from 5 (3 x + 5) + x (3 x + 5):
Answer: (3 x + 5) (x + 5)
Answer:
b
Step-by-step explanation:
Displacement and distance have different meanings. Displacement is a vector quantity and is the objects overall change in position. Distance is scalar quantity which describes how much ground an object covers during motion.
If they have covered 4 miles from a origin and we don't know the origin but we know that they start there and continue for 4 miles. It will be displacement if they started at a distance and walked a certain distance and the difference from start to finish is 4 miles. Therefore, it must be distance because we don't know the initial position and only that they walked 4 miles.
Mark is right if their starting point is a origin of a coordinate system
The answer is 2x^3
Because there are two of the same squares and the volume of a square is x^3
Answer:
5 to 9 5:9 5/9
Step-by-step explanation:
