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juin [17]
3 years ago
10

Calculate the size of a cube​

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
4 0

Answer:

<em>A</em><em> </em><em>cube</em><em> </em><em>size</em><em> </em><em>is</em><em> </em><em>150mm</em>

Step-by-step explanation:

I think it will be

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Answer: 50x+100\geq18,000

Step-by-step explanation:

Let w denotes a seven letter word which Sal will need to make to break the record.

Since  you get 50 points for each seven-letter and 100 points for playing the game.

Then the total points earned by you by making w seven letters words will be:

50x+100

Since, Sal wants to break that record, and needs 18,000 points or more to do so.

Then , the required inequality will be :

50x+100\geq18,000

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3 years ago
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Necesito encontrar expresiones equivalentes a los valores del 1 al 20 pliss
Mariulka [41]

Answer and Step-by-step explanation:

Si está buscando una expresión que sea igual a los números del 1 al 20, intente hacer una. Por ejemplo, 2y + 1x = 18 donde y = 9 - x / 2 y x = 18 - 2y. Siempre que la expresión sea igual a menos de 20, ¿no?

Lo siento, no entendí muy bien la pregunta, ¡pero espero que esto te haya ayudado! ¡Ten un día maravilloso! <3

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4 0
3 years ago
Write the equation in logarithmic form 4^7=16,384 please show work
nlexa [21]

 If a^ x = b then:  

x = log_{a}b  

For:

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8 0
3 years ago
The zeros for f(x)=x^4-4x^3-9x^2+36x are
Mrrafil [7]
X^4 - 4x^3 - 9x^2 + 36x = 0
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x(x^2(x - 4) - 9(x - 4) = 0
x(x + 3)(x - 3)(x - 4) = 0

the zeroes are  -3, 0, 3, 4  Answer
3 0
3 years ago
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
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