In circle J with mZHIK = 54 and HJ = 13 units find area of sector
1 answer:
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Answer:
m<E =
Step-by-step explanation:
From the diagram, ΔACE and ΔBDE are similar. So that comparing its angles, we have;
(8x + 4) = (9x - 5)
8x + 4 = 9x - 5
5 + 4 = 9x - 8x
x = 9
Thus,
(8x + 4) = 8(9) + 4 = 76
(9x - 5) = 9(9) - 5 = 76
3x = 3(9) = 27
From ΔACE,
3x + (8x + 4) + m<E = 180 (sum of angles in a triangle)
27 + 76 + m<E = 180
m<E = 180 - 103
m<E =
11,580 to 3 significant figures
Currently, the value has 5 significant figures ( inclusive of 0 )
next to 5, there is 8 and 8 > 5, so 5 rounds up
1.16 x 10⁴
Currently, the value has 5 significant figures ( inclusive of 0 )
next to 5, there is 8 and 8 > 5, so 5 rounds up
1.16 x 10⁴