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Ann [662]
1 year ago
15

Write 0.8 as a fraction. thank youuu

Mathematics
1 answer:
Lady_Fox [76]1 year ago
3 0

Answer:

8/9

Step-by-step explanation:

The other answer is wrong because the problem is asking for the fraction form of 0.8 repeating, not just 0.8.

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What property is shown here? (1 x 4) x 3 = 1 x (4 x 3)
irinina [24]
Answer:Associative Property of Multiplication
4 0
4 years ago
Write 3 1/8 as a decimal.
Alenkinab [10]
No it is not. It is a fraction
5 0
4 years ago
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Create a quadratic polynomial function f(x) and a linear binomial in the form (x − a).
erik [133]
Quadratic polynomial  x^2 - x - 6 = f(x)
binomial  (x-3)

dividing:-
                x   + 2
          ----------------------
x - 3   )  x^2  - x   -  6
             x^2 - 3x
             ----------
                     2x - 6
                     2x - 6
                     --------
                      .........

result of division is (x + 2)  
s o we can write the function as (x - 3)(x + 2)

Part 2  f(a)  = f(3)   =  (3)^2 - 3 - 6 = 0

Part3  The remainder Theorem  states that  the remainder when a polynomial is divided by (x - a)  then the remainder is f(a).  If f(a) = 0 then  x - a is a factor.
In the above case f(3) = 0 therefore (x - 3) is a factor of our polynomial.
7 0
3 years ago
PLEASE HELP! sketch y = 3x − 2
nordsb [41]

Answer:

The graph of the equation y=3x-2 is shown in the picture below!!

Step-by-step explanation:

I hope this helps, if it does please mark brainliest!! Thank you!! Have a great day!

3 0
3 years ago
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Solve the equation f(x) = g(x) by graphing the functions f(x)= 2^x + 1 and g(x) = 5 on the same set of coordinate axes.
saveliy_v [14]

Answer:

C) The ordered pair that contains a solution to the equation lies in Quadrant I.

D) The solution to the equation is x = 2

Step-by-step explanation:

we have

f(x)= 2^x + 1

g(x)= 5

f(x)=g(x)

we know that

The solution is the x-coordinate of the intersection point both graphs

using a graphing tool

The intersection point is (2,5)

therefore

The solution is x=2

see the attached figure

<u>Verify each statement</u>

case A) The ordered pair that contains the solution to the equation lies in Quadrant II

The statement is False

The ordered pair that contains the solution to the equation lies in the first quadrant

case B)There are 2 solutions to the equation

The statement is False

The equation has only one solution

case C) The ordered pair that contains a solution to the equation lies in Quadrant I.

The statement is True (see the procedure)

case D) The solution to the equation is x = 2

The statement is True  (see the procedure)

case E) The ordered pairs that contain the solutions to the equation lie in Quadrant I and II

The statement is False

The ordered pair that contain the solution to the equation lie in Quadrant I

3 0
3 years ago
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