Answer:
(7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance.
Step-by-step explanation:
We have a large sample size n = 56 research cotton samples. Besides,
and
. A 95% large-sample CI for the true average percentage elongation is given by
, i.e.,
or equivalently (7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance because we have a large sample.
Step-by-step explanation:
m+3=9
m=9-3=6
The second question I guess that it is solved like
2x+5=11
2x=11-5
2x=6
X=3
Or the other qusetion 5x-8=27
5x=19
X=19/5
I don't know the machine so sorry
Answer:
option 2
hope this helps
have a good day :)
Step-by-step explanation:
The answer would be D how are the trails used