A soccer team is having a car wash the team spent $75 on supplies and $260 including tips....

kupik [55]

So, let's begin...
First off, you must note that the question is asking for the d value when you substitute the value of c(x).
You are given the following information:
1. The c(x) value is already given to be 0.75x.
2. The equation to find d of (any value) is 0.8y-5.

So, substitute the value of 0.75x as a y value into 0.8y - 5. This is because you are substituting the value of c(x) for d. This is equal to 0.8 times 0.75x - 5. This is equal to 0.6x - 5, which is the function. Thus, your final answer is d(c(x)) = 0.6x - 5.
If you have any questions please comment. Otherwise, hope this helps! :)

6 0

2 years ago

How would I be able to get the step by step prosses of this and the answer of y?

Daniel [21]

Answer:

y = 3

Step-by-step explanation:

-7 = -4y + 5

Subtract 5 from both sides to isolate variable y:

-7 - 5 = -4y + 5 - 5

-12 = -4y + 0

-12 = -4y

Divide both sides by -4 to isolate variable y:

-12 ÷ -4 = -4y ÷ -4

(Negative ÷ Negative = Positive)

3 = 1y

3 = y

Check your work:

-7 = -4(3) + 5

Use PEMDAS:

-7 = -12 + 5

-7 = -7

Correct!

6 0

2 years ago

22. Tiffany ran 5/6 mile. Shayne ran 3/4 mile. Who ran<br>_farther? How much farther?

Fiesta28 [93]

Answer: Tiffany by 1/12 of a mile

Step-by-step explanation:

Find the common denominator and compare both of them

7 0

2 years ago

Read 2 more answers

Which equation represents the statement: Three times the sum of a number and 5 is –30?

castortr0y [4]

Answer:

3(n+5)=-30

Step-by-step explanation:

Three times the sum of a number and 5 is - 30

Vocabulary:

times = multiplication, represented with *

sum = addition, represented by +

unknown number = n

Three * the sum of a number and 5

The sum of a number and 5 is the same as saying n + 5

So we are multiplying 3 by n + 5

Because n is an unknown variable we have to separate the sum of n and 5 from being multiplied by 3 with parenthesis. We do this because if we want to multiply 3 by the sum of n and 5. If we put 3 * n + 5 we are only multiplying the unknown variable by 3 not including the 5 that is added to it.

So we get 3( n + 5 ) is -30

3(n+5)=-30 is the answer.

3 0

1 year ago

Read 2 more answers

Match each function with the corresponding function formula when h(x)=5-3x and g(x)=-3+5

Grace [21]

Answer:

k(x) = (3g + 5h)(x) ⇒ (1)

k(x) = (5h - 3g)(x) ⇒ (3)

k(x) = (h - g)(x) ⇒ (2)

k(x) = (g + h)(x) ⇒ (4)

k(x) = (5g + 3h)(x) ⇒ (5)

k(x) = (3h - 5g)(x) ⇒ (6)

Step-by-step explanation:

* To solve this problem we will substitute h(x) and g(x) in k(x) in the

right column to find the corresponding function formula in the

left column

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

- Lets start with the right column

# k(x) = (3g + 5h)(x)

∵ g(x) = -3^x + 5

∵ 3g(x) = 3[-3^x + 5] = [3 × -3^x + 3 × 5]

- Lets simplify 3 × -3^x

take the negative out -(3 × 3^x), and use the rule a^n × a^m = a^(n+m)

∴ -3(3 × 3^x) = -(3^x+1)

∴ 3g(x) = -3^x+1 + 15

∵ h(x) = 5 - 3x

∵ 5h(x) = 5[5 - 3x] = [5 × 5 - 5 × 3x] = 25 - 15x

- Now substitute 3g(x) and 5h(x) in k(x)

∵ k(x) = (3g + 5h)(x)

∴ k(x) = -3^x+1 + 15 + 25 - 15x ⇒ simplify

∴ k(x) = 40 - 3^x+1 - 15x

∴ k(x) = 40 - 3^x+1 - 15x ⇒ k(x) = (3g + 5h)(x)

* k(x) = (3g + 5h)(x) ⇒ (1)

# k(x) = (5h - 3g)(x)

∵ 5h(x) = 25 - 15x

∵ 3g(x) = -3^x+1 + 15

∵ k(x) = (5h - 3g)(x)

∴ k(x) = 25 - 15x - (-3^x+1 + 15) = 25 -15x + 3^x+1 - 15 ⇒ simplify

∴ k(x) = 10 + 3^x+1 - 15x

∴ k(x) = 10 + 3^x+1 - 15x ⇒ k(x) = (5h - 3g)(x)

* k(x) = (5h - 3g)(x) ⇒ (3)

# k(x) = (h - g)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (h - g)(x)

∴ k(x) = 5 - 3x - (-3^x + 5) = 5 - 3x + 3^x - 5 ⇒ simplify

∴ k(x) = 3^x - 3x

∴ k(x)= 3^x - 3x ⇒ k(x) = (h - g)(x)

* k(x) = (h - g)(x) ⇒ (2)

# k(x) = (g + h)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (g + h)(x)

∴ k(x) = -3^x + 5 + 5 - 3x ⇒ simplify

∴ k(x) = 10 - 3^x - 3x

∴ k(x)= 10 - 3^x - 3x ⇒ k(x) = (g + h)(x)

* k(x) = (g + h)(x) ⇒ (4)

# k(x) = (5g + 3h)(x)

∵ g(x) = -3^x + 5

∵ 5g(x) = 5[-3^x + 5] = [5 × -3^x + 5 × 5] = 5(-3^x) + 25

∴ 5g(x) = -5(3^x) + 25

∵ h(x) = 5 - 3x

∵ 3h(x) = 3[5 - 3x] = [3 × 5 - 3 × 3x] = 15 - 9x

- Now substitute 5g(x) and 3h(x) in k(x)

∵ k(x) = (5g + 3h)(x)

∴ k(x) = -5(3^x) + 25 + 15 - 9x ⇒ simplify

∴ k(x) = 40 - 5(3^x) - 9x

∴ k(x) = 40 - 5(3^x) - 9x ⇒ k(x) = (5g + 3h)(x)

* k(x) = (5g + 3h)(x) ⇒ (5)

# k(x) = (3h - 5g)(x)

∵ 3h(x) = 15 - 9x

∵ 5g(x) = -5(3^x) + 25

∵ k(x) = (3h - 5g)(x)

∴ k(x) = 15 - 9x - [-5(3^x) + 25] = 15 - 9x + 5(3^x) - 25 ⇒ simplify

∴ k(x) = 5(3^x) - 9x - 10

∴ k(x) = 5(3^x) - 9x - 10 ⇒ k(x) = (3h - 5g)(x)

* k(x) = (3h - 5g)(x) ⇒ (6)

4 0

2 years ago