Answer:
Solution given:
opposite:9
adjacent: 12
Relationship between opposite and adjacent is given by tan angle
so
#11.
hypotenuse[h]=11cm
opposite/perpendicular[P]=b cm
adjacent/base[b]=a cm
now
Relationship between height and hypotenuse is given by Sin angle
:.
Sin 62°=
doing crisscrossed multiplication
b=Sin 62°*11
:.b=9.71 cm
a) At <u>9</u><u>.</u><u>7</u><u>1</u><u> </u>cm height does the ladder touch the building.
again
Relationship between base and hypotenuse is given by Cos angle
:.Cos 62°=
doing crisscrossed multiplication
a=Cos 62°×11
a=5.16cm
b) the distance between the foot of the ladder and the building is <u>5.16cm.</u>
For
y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
y = (x -2)/(x^2 -49)
There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.
Use the factor theorem to determine whether the first polynomial is a factor of the second polynomial x-3;2x^2-4x+30
x−3,2x^2−4x+30
Step-by-step explanation:
You need to translate all the points to the right 3 and up 6
Therefore, you are going to use this formula:
(x,y) ⇾ (x + 3, y + 6)
This is the same format as the previous problem, if you have noticed.
Using this, plug in each coordinate, starting with P (5, -1)
(5, -1) ⇾ ( 5 + 3, -1 + 6)
(5, -1) ⇾ ( 8, 5 )
P
= (8, 5)
Now point Q, (0, 8)
(0, 8) ⇾ (0 + 3, 8 + 6)
(0, 8) ⇾ ( 3, 14 )
Q = (3, 14)
And last but not least, the point R, (7, 5)
(7, 5) ⇾ (7 + 3, 5 + 6)
(7, 5) ⇾ ( 10, 11 )
R = (10, 11)
Therefore, P = (8, 5), Q = (3, 14), R = (10, 11) is your answer. This is the 4th option or D.
Hope this for you to understand this a bit more! =D
