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saul85 [17]
2 years ago
7

Whats the answer HELP giving brainliest

Mathematics
1 answer:
mario62 [17]2 years ago
8 0
I’m pretty sure B because 1/4 divided by 1/2 equals 1/2 and that the only one that has a model that has 1/2 but don’t take my word for it
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What is the least common multiple of 6 and 17?<br>​
amm1812

Answer:

102

Step-by-step explanation:

The least common multiple of 6 and 17

For us to determine the L.C.M of 6 and 17,

First find the prime factors of 6 and 17

Prime Factor of 6

6 = 2 × 3

Prime factor of 17

17 = 1 × 17

Secondly;

Multiply all the factors together to find the L.C.M:

L.C.M = 1 × 2 × 3 × 17

L.C.M = 102

Please mark as brainliest

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2 years ago
In a controlled laboratory environment, a random sample of 10 adults and a random sample of 10 children were tested by a psychol
Semmy [17]

Answer:

a) It cannot be concluded at the 99% confidence level that there is actually a difference between the true mean comfortable room temperatures for the two groups.

Step-by-step explanation:

8 0
2 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT
tatiyna
The first one is correct
5 0
2 years ago
An insect is 3.5 millimeters long. Which expression finds the length of the insect in decimeters? Use the metric table to help a
Katarina [22]

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Step-by-step explanation:

youre welcome

7 0
3 years ago
Read 2 more answers
What is the value of d21+d22+d23 given the matrix equation below?
sleet_krkn [62]

Answer:

B. 8

Step-by-step explanation:

The question lacks the required diagram. Find the diagram in the attachment.

Before we can find d21, d22 and d23, we need to get the matrix D first as shown in the attached solution.

On comparison as shown in the attachment, d21 = 11, d22 = -10 and d23 = 7

Note that d21 refers to element in the second row and first column of the matrix

d22 is the element in the second row and second column of the matrix

d23 is the element in the second row and third column of the matrix

d21+d22+d23 = 11-10+7

d21+d22+d23 = 8

The second option is correct.

5 0
3 years ago
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