3p^4(4p^4 + 7p^3 + 4p + 1)
<span>=<span><span>(<span>3<span>p^4</span></span>)</span><span>(<span><span><span><span>4<span>p^4</span></span>+<span>7<span>p^3</span></span></span>+<span>4p</span></span>+1</span>)</span></span></span><span>=<span><span><span><span><span>(<span>3<span>p^4</span></span>)</span><span>(<span>4<span>p^4</span></span>)</span></span>+<span><span>(<span>3<span>p^4</span></span>)</span><span>(<span>7<span>p^3</span></span>)</span></span></span>+<span><span>(<span>3<span>p^4</span></span>)</span><span>(<span>4p</span>)</span></span></span>+<span><span>(<span>3<span>p^4</span></span>)</span><span>(1)</span></span></span></span><span>=<span><span><span><span>12<span>p^8</span></span>+<span>21<span>p^7</span></span></span>+<span>12<span>p^5</span></span></span>+<span>3<span>p^<span>4</span></span></span></span></span>
Answer:
d=5
Step-by-step explanation:
Answer:
0.66
Step-by-step explanation:
The exponential growth equation is expressed as;
S(t) = S0e^kt
S(t) is the number of stores after t years
S0 is the initial number of stores
If a chain of retail computer stores opened 2 stores in its first year of operation then at t = 1, S(t) = 2. Substitute into the equation;
2 = S0e^k(1)
2 = S0e^k .... 1
Also if after 8 years of operation, the chain consisted of 206 stores, this means at t = 8, S(t) = 206. Substitute into the equation;
206 = S0e^k(1)
206 = S0e^8k .... 2
Next is to calculate the value of k
Divide equation 2 by 1;

Hence the value of k to the nearest hundredth is 0.66
Answer:
x squared+4x−12
Step-by-step explanation: