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frutty [35]
3 years ago
5

Factor completely: 64x^3+1

Mathematics
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

Step-by-step explanation:

Sum of cubes is a^3+b^3=(a+b)(a^2-ab+b^2)

64x^3+1

(4x+1)(16x^2-4x+1)

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Use the Laplace transform to solve the given initial value problem. y' + 6y = e^4t ; y(0)=2 ...?
TiliK225 [7]
Performing laplace transform of the equation.

sY(s) - y(0) + 6Y(s) = 1/(s-4)
(s+6)Y(s) - 2 = 1/(s-4)
Y(s) = 2/(s+6) + 1/(s-4)(s+6), by partial fraction decomposition
Y(s) = 2/(s+6) + 1/10 * (1/(s-4) + 1/(s+6))
Y(s) = 0.1/(s-4) + 2.1/(s+6)

Performing inverse laplace transform,
y(t) = 0.1e^4t + 2.1e^(-6t)


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
1 fourth B minus 10 equals 7
creativ13 [48]
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Step-by-step explanation:

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