So xy=-60 and x+y=-28
x+y=-28 also means x=-28-y
subsitute x=-28-y for x in xy=-60
(-28-y)y=-60
-28y-y^2=-60
add negative y^2 to both sides
-28y=-60+y^2
add 28y to both sides
0=y^2+28y-60
factor
0=(x-2)(x+30)
we set them to zero
x-2=0
x=2
x+30=0
x=-30
the numbers could be -30 and 2
Answer:
1. 5xy^3
2. 4/9m^6 n^4
3. 2a^2/c
4. 4x^3m+6/3
Step-by-step explanation:
Answer:
2nd option is correct
Step-by-step explanation:
this would be using the ASA congruence theorem.
7.50
25% also equals 1/4 so divide 130.00 by 4 which equals 32.50
subtract 32.50 from 130.00 which equals the cost, 97.50
97.50 minus 90$ is 7.50, therefore that is the answer
