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lozanna [386]
3 years ago
13

If you got 1 wrong on a test that had 5 questions, how did you do? I got a D

Mathematics
2 answers:
lianna [129]3 years ago
8 0
So 4/5 should be an 80 because if you multiply 5x20 and 4x20 you would get 80/100 but sometimes teachers make certain questions worth more points than others so maybe that is what happened but maybe talk to your teacher about it
laila [671]3 years ago
7 0

Answer:

80% (B)

Step-by-step explanation:

  1. Divide the max grade (100) by 5 questions, which is 20.
  2. If you got 4 correct (1 wrong), you need to multiply 20 by 4, which is 80%. 80-89's are Bs (well at least where I live)
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5
Dvinal [7]
Answer B

Explanation: Y=mx+b
M=slope and b=yintercept
6 0
3 years ago
The longest side of the right triangle is 2 feet more than the middle side and the middle side is 1 foot less than twice the sho
Ket [755]
A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8
3 0
3 years ago
HELP!!! PLZZ THIS IS SO FRICKIN HARD!
krek1111 [17]

Answer:

14.3%

Step-by-step explanation:

1/7=0.142857142857

round that to the nearest tenth and that is 0.143

make it a percentage and it is 14.3%

8 0
2 years ago
What is the slope of this line?
PIT_PIT [208]

Answer:

It has a slope of 1.

Step-by-step explanation:

First, you need to choose two points. The points HAS to be exactly on top of the line.

The two points I picked where

(-2,0) and (-1,1)

All you do is subtract the two points. Remember rise over run or y/x

1 -0 = 1

-1 - (-2) = 1

6 0
2 years ago
Plz help w this math problem
Svetllana [295]

Answer:

• for x = 2a√t, make t the subject:

{ \tt{x = 2a \sqrt{t} }} \\  \\ { \tt{ \sqrt{t}  =  \frac{x}{2a} }} \\  \\ { \boxed{ \tt{t =  \frac{ {x}^{2} }{4 {a}^{2} } }}}

• then find y:

{ \tt{y =  {ar}^{2}  - 2at}} \\  \\ { \tt{y =  {ar}^{2} - 2a( \frac{ {x}^{2} }{4 {a}^{2} } ) }} \\  \\ { \boxed{ \tt{y =  {ar}^{2} -  \frac{ {x}^{2} }{2a}  }}}

6 0
3 years ago
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