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3 years ago

Choose the most appropriate answer.

Mathematics

1 answer:

ANTONII [103]3 years ago

4 0

Answer:

The answer its A:

Step-by-step explanation:

I hope its correct.

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Answer the following questions if x=3 what is the value of <br><br>2x+5 11-3x x²+4x<br>

Ainat [17]

Answer:

Step-by-step explanation:

hello :

2x+5 11-3x x²+4x

x=3 : 2(3)+5+11-3(2)+(3²)+4(3) ...continu

3 0

3 years ago

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if the denominator of 2/3 is increased by number and the numerator is doubled the result is 1 find the number

Sophie [7]

2/3
denominator is increased by a number so 3+a
numerator is doubled so 2(2)= 4
in order for it to be a whole (or 1) then it would have to be 4/4
so 4-3=1
the number is 1

6 0

4 years ago

Read 2 more answers

Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)

Allisa [31]

Part A:

Given the function $f(x)=x+2\cos(x)$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow1-2\sin{x}=0 \\ \\ \Rightarrow2\sin{x}=1 \\ \\ \Rightarrow\sin{x}= \frac{1}{2} \\ \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}$

Using the second derivative test,

$f''(x)=-2cosx \\ \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732$

Since the second derivative gives a negative number, the given function has a maximum point at $x=\frac{\pi}{6}$ .

And the maximum point is given by:

$f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\ \\ =0.5236+2(0.8660)=0.5236+1.732 \\ \\ =\bold{2.256}$

i.e. $\left(\frac{\pi}{6},\ 2.256\right)$

Part B:

Given the function $f(x)=e^{-x}-e^{-2x}$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\ \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\ \\ \Rightarrow x=0.6931$

Using the second derivative test,

$f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\ \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\ \\ =-0.5$

Since the second derivative gives a negative number, the given function has a maximum point at $x=0.6931$ .

And the maximum point is given by:

$f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\ \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}$

i.e. (0.693, 0.25)

3 0

3 years ago

Why is 130 oz bigger than 8 lbs

nordsb [41]

130 oz is bigger than 8 pounds because 1 pound is equal to 16 oz

3 0

4 years ago

Is y=x2-1 a linear equation

Inga [223]

Y=x2-1 is not a linear equation only because for it to be an linear equation it would have to be 2x-1=y or y=2x-1

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3 years ago