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alexgriva [62]
3 years ago
6

Find the slope of the line for (1,6) and (8,-1)

Mathematics
1 answer:
wlad13 [49]3 years ago
5 0
When given two points you use the slope formula m=y2-y1 over x2-x1
(x1 , y1) and (x 2 , y 2)
(1 , 6)    and  (8, -1)

m= -1-6 / 8-1
m= -7 / 7
m = -1

slope equals 1
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What are the roots of f(x) = x2 – 48? –48 and 48 –24 and 24 Negative 8 StartRoot 3 EndRoot and 8 StartRoot 3 EndRoot Negative 4
Ivanshal [37]

Answer:

x=4\sqrt{3},\:x=-4\sqrt{3} are the roots.

Step-by-step explanation:

x=4\sqrt{3},\:x=-4\sqrt{3}

Considering the expression

x^2\:-\:48

Solving

x^2-48=0

x^2-48+48=0+48

x^2=48

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{48},\:x=-\sqrt{48}

Solving

x=\sqrt{48}

  = \sqrt{2^4\cdot \:3}

  \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

  = \sqrt{3}\sqrt{2^4}

  \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^m}=a^{\frac{m}{n}}

  \sqrt{2^4}=2^{\frac{4}{2}}=2^2

  =2^2\sqrt{3}

  =4\sqrt{3}

So,

x=4\sqrt{3}

Similarly,

x=-\sqrt{48}=-4\sqrt{3}

Therefore, x=4\sqrt{3},\:x=-4\sqrt{3} are the roots.

Keywords: roots, expression

Learn more about roots from brainly.com/question/3731376

#learnwithBrainly

9 0
3 years ago
Read 2 more answers
Need the answer asap
Vikki [24]
B I think.correct if I’m wrong
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2 years ago
The function f (t) = 12(1 +0.03) can be used to determine the population, in thousands of a town t years
Alja [10]

f= the original amount of people, a steady growth throughout the years

t=time

In 1955 the population was 12 thousand. Compared to the current population of 12.36 thousand, the population then was roughly 77%.

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2 years ago
Please show ur work
Fiesta28 [93]
B. 1/7 i just took the test and thats what i got hope it helps


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3 years ago
What is the value of the expression<br> below when x<br> =<br> 6 and y<br> -4 ?
tester [92]

Answer:

-2

Step-by-step explanation:

Plug in the respected values for x and y.

Divide and get -2

8 0
2 years ago
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