Use two points from the graph to check if they are constant. In this case let’s use (0,50) & (2,58)
To find slope you have to do the following.
y2-y1 / x2-x1
Plug in the values, 58-50/2-0
This gives you 4.
When you use two other points, in this case (10,90) (20,130) you get a slope of 4.
This means the slope is 4.
We are trying to get an equation of y=mx+b.
We have slope already which is 4. So now we plug in y=4x + b
Now we need to find b. There is an equation to solve for b. Which is b=y1-m(x1)
But b is the y-intercept so there is already a B which is 50
So the table IS a linear equation and the equation is y=4x+50.
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Step-by-step explanation:
I am very sure that the answer is V≈351.86
Answer:
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Step-by-step explanation:
Answer:
Given statement is TRUE.
Step-by-step explanation:
Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.
We know that corresponding angles formed by transversal line are congruent.
Hence ∠JKL = ∠ MLK ...(i)
Now consider triangles JKL and MLK
JK = LM {Given}
∠JKL = ∠ MLK { Using (i) }
KL = KL {common sides}
Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.
Hence given statement is TRUE.
