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GrogVix [38]
3 years ago
12

The first term of a geometric sequence is 1, and the common ratio is 10. What is the 10th term of the sequence?

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0
T(10)=1(10)^9=1000000000
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What times what equals 18
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9 x 2 = 18
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Answer:

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Simplify the following algebraic expression:<br> 4+3 [6z - 5(6 +2z)]
Tatiana [17]

\huge\text{Hey there!}

\huge\text{4+3 [6z - 5(6 +2z)]}

\huge\text{4+(3)(6z)+(3)(-5(6+2z))}\\\\\rightarrow\huge\text{4+18z+(-30z)+(-90)}

\huge\text{\bf{Combine the like terms if you have any.}}

\huge\text{Like term \#1: 10z \& -30z}\\\\\\\huge\text{Like term \#2: 4 \& -90}

\huge\text{18z + (-30z) + (4 + (-90))}

\huge\text{18z + (-30z) = -12z}\\\\\\\huge\text{4 + (-90) = -86}

\boxed{\boxed{\huge\text{Answer: -12z + (-86)}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

5 0
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Robert went to the grocery store and purchased cans of soup and frozen dinners. each can of soup has 300 mg of sodium and each f
Paraphin [41]

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Step-by-step explanation:

Let,

Soup = x

Frozen Dinner = y

According to given statement of sodium;

300x + 500y = 5200 eqn 1

And,

x + y = 14 eqn 2

Multiplying\ equation\ 2\ with\ 300\\300(x+y=14)\\300x+300y=4200\ Eqn 3\\

Subtracting Eqn 3 from Eqn 1;

(300x+500y)-(300x+300y)=5200-4200\\300x+500y-300x-300y=1000\\200y=1000\\y=\frac{1000}{200} \\y=5

Putting value of y in Eqn 1;

300x+500(5)=5200\\300x+2500=5200\\\\Subtracting\ 2500\ from\ both\ sides\ \\300x+2500-2500=5200-2500\\300x=2700\\x=\frac{2700}{300} \\x=9

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Keywords: Variables, linear equations, subtraction.

Learn more about linear equations at;

  • brainly.com/question/5047646
  • brainly.com/question/5048216

#LearnwithBrainly

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3 years ago
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