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zzz [600]
3 years ago
13

Please help with these two (I will report you if you try to give me a link to a virus)

Mathematics
2 answers:
Ganezh [65]3 years ago
7 0
1- false a positive is greater than a negative so clearly there could be positive answers to the inequality. 2-true since the numbers and sign flipped it would still be the same
Gemiola [76]3 years ago
5 0

Answer:

1 answer will be false and second answer will be true

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Write the first four multiples of each number.<br><br>1. 3 <br>2. 4<br>3. 8 <br>4. 15
Levart [38]

Answer:

3, 6, 9, 12

4, 8, 12, 16

8, 16, 24, 32

15, 30, 45, 60

Step-by-step explanation:

multiply each number by itself

5 0
3 years ago
In problems 1-3, a and b are legs and c is the hypotenuse. Find the missing side length of the
Readme [11.4K]

Answer:

1. b=39.497

2. c=3.606

3. a=18.974

Step-by-step explanation:

1.

41^2-11^2=b^2

1681-121=b^2

b^=1560

b=39.497

2.

2^2+3^2=c^2

4+9=c^2

c^2=13

c=3.606

3.

21^2-9^9=a^2

441-81=a^2

a^2=360

a=18.974

4 0
3 years ago
Scott buys candy that costs $7 per kilogram. He will spend at least $35 on candy. What are the possible numbers of kilograms he
slega [8]

Answer:

<em>p ≥ 5</em>

<em>Scott will buy at least 5 kilograms of candy.</em>

Step-by-step explanation:

<u>Inequalities</u>

The candy Scott buys cost $7 per kilogram.

Let's set p=number of kilograms of candy Scott will buy.

The money spent to buy p kilograms of candy is 7p dollars.

The condition states he will spend at least $35 on candies, thus the following inequality is formed:

7p ≥ 35

Dividing by 7:

p ≥ 35/7

Operating:

p ≥ 5

Scott will buy at least 5 kilograms of candy.

3 0
3 years ago
Solve each system by substitution. please help me<br> 2x{+y=6<br> x{+y=3
saw5 [17]
1. x= 3/Y as a fraction btw

2. Same thing
6 0
3 years ago
The Miguel traces a circle with the radius of 25 cm like the one shown. He will color the shade section what is the area of the
Scilla [17]

Answer: The area of shaded section is 491.07 cm²

Step-by-step explanation:

Given: Radius of the circle = 25 cm

Now as shown in figure the shaded region is a quadrant.

Therefore the central angle is 90°

Now as we know

Area of sector is given by

Area= \pi r^2 \dfrac{\theta}{360^\circ}  where r is radius and \theta is central angle

So we have

Area = \dfrac{22}{7} \times (25)^2\times \dfrac{90^\circ}{360^\circ} \\\\\Rightarrow Area=  \dfrac{22}{7} \times 625 \times \dfrac{1}{4} \\\\\Rightarrow Area=  \dfrac{11}{7} \times 625 \times \dfrac{1}{2} = 491.07cm^2

Hence, the area of shaded section is 491.07 cm²

5 0
3 years ago
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