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iragen [17]
3 years ago
13

Please help im so confused at math pls help

Mathematics
1 answer:
exis [7]3 years ago
6 0

Answer:

where is the question ??

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1. Which situation is best described by the
liberstina [14]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Jessie has 160 rubber bracelets. She arranges the bracelets in piles of 40. Which model shows 160 ÷ 40?
Sergio [31]

Answer:

I am not sure what model you are talking about, no options to choose from

Step-by-step explanation:

You can divide both by 10, making the problem 16 / 4, which would look like 4 piles of four.

This means that the model that looks like 4 groups of 40

5 0
3 years ago
What is the area of this shape
Tema [17]
This is the area of a trapezoid and the formula for that is:
.5(h)(b1 + b2) where h is height and b1 and b2 are the base length or the length of the parallel sides.  therefore, our area is:
.5(16)(6+12)
8(18)
144
if you're wondering why the area formula works, construct another trapezoid but this time upside-down.  now flip it along it's height axis so you can align one of the side lengths of the 2 trapezoids and you have a parallelogram.
the base of this parallelogram is b1+b2 of the original trapezoid and the height still remains h so the area of this parallelogram is (h)(b1 + b2).  however, we want to find the area of the trapezoid but we find that the parallelogram is twice the area of our trapezoid so the area of the trapezoid is half the area of the parallelogram.  so area = .5(h)(b1 + b2).

let me know if you have any questions!
4 0
3 years ago
write a variable expression to describe the rule of each progression then calculate the term 20 or 20 term1.) 6,12,18,24,...2.)3
Dmitriy789 [7]

1) 6, 12,18,24

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 6, d = 6

\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 6 + 19}\times6 \\ T_{20\text{ }}\text{ = 6 + 114} \\ T_{20\text{ }}\text{ = 120} \end{gathered}

2) 3,6,9,12

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 3, d = 3

\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 3 + 19 }\times3 \\ T_{20\text{ }}\text{ = 3 + 57} \\ T_{20\text{ }}\text{ = 60} \end{gathered}

3) 1,5,9,13

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 1, d = 4

\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 1 + 19 }\times4 \\ T_{20\text{ }}\text{ = }1\text{ + 76} \\ T_{20\text{ }}\text{ = }77 \end{gathered}

5 0
1 year ago
-9.69*10^6 over 3*10^-9 in scientific notation
ira [324]
It would be = -3.23 * 10^15
7 0
3 years ago
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