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iragen [17]
3 years ago
13

Please help im so confused at math pls help

Mathematics
1 answer:
exis [7]3 years ago
6 0

Answer:

where is the question ??

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What are the constants in the expression below? 12x -3.7 -8y +1/3
Fantom [35]
Anything without a variable in front.

In other words, the constants are -3.7 and 1/3 
5 0
3 years ago
Read 2 more answers
3D In the cryptarithm shown, different letters stand for different digits, and no leading digit can equal 0. Find the greatest p
svp [43]

Answer:

1961

Step-by-step explanation:

The greatest value of OFF can be achieved by making the hundreds places the greatest, followed by the tens, and then the ones.

S=9

A=8

U=7

T=6

N=5

986+975=1961

7 0
3 years ago
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ANOTHER ONE PLEASE.......HELP ME....
Flura [38]
The answer is 5,129
7 0
3 years ago
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8 and 10 in independent practice please
Sergeeva-Olga [200]

Answer:

8.) Rational

10.) Irrational

Step-by-step explanation:

8.) This is rational because although it is a decimal, it is terminating, meaning it has an end.

10.) This is irrational because it is a repeating decimal with seemingly no pattern.

7 0
3 years ago
3. Two balls are drawn in succession without replacement from an urn containing 4 red balls and 3 blue balls. Find the probabili
choli [55]

Answer:

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

Step-by-step explanation:

Given that :

Number of red balls = 4

Number of Blue balls = 3

Total number of balls = (4 + 3) = 7

Picking without replacement :

Number of picks = 2

1st pick is red :

Probability = (required outcome / Total possible outcomes)

USing combination formula :

nCr = n! / (n-r)! r!

Total possible outcome :

7C2 = 7! / 5!2! = 7*6 / 2 = 42 / 2 = 21

X = number of red

For red = 0;

P(x =0) = required outcome / Total possible outcomes

P(x = 0)

Required outcome : [4C0 * 3C2)]

P(x = 0) = [(4C0 * 3C2)] / 21 = (1*3)/21 = 3/21 = 1/7

P(x = 1)

Required outcome : [4C1 * 3C1)]

P(x = 1) = [(4C1 * 3C1)] / 21 = (4*3)/21 = 12/21 = 4/7

P(x = 2)

Required outcome : [4C2 * 3C0)]

P(x = 2) = [(4C2 * 3C0)] / 21 = (6*1)/21 = 6/21 = 2/7

Hence ;

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

8 0
3 years ago
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