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FinnZ [79.3K]
3 years ago
10

Need help with this linear algebra problem

Mathematics
1 answer:
kap26 [50]3 years ago
4 0

You should have

L(t)=\begin{bmatrix}1\\1\end{bmatrix}+t\begin{bmatrix}2\\-3\end{bmatrix}

\mathbf v on its own points to the point (2, -3) and lies on the line through this point and the origin. We capture all points on this line by scaling \mathbf v by t. Then we add to t\mathbf v another vector that points to P(1, 1), which shifts the endpoint of all vectors on the line t\mathbf v to the line through P that runs parallel to t\mathbf v.

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3 0
3 years ago
Can anyone please help me with my math homework!!!
Lena [83]
Number 8 is 24 hope I help please give me brainiest<span />
7 0
3 years ago
On a floor plan drawn at a scale of 1:100, the area of a rectangular room is 30
Troyanec [42]
Assume that the dimensions of the room in the plan are a (width ) by b (length),

such that a*b=30.

Since the scale is 1:100, a represents 100a, and b represents 100b.

So the actual dimensions are 100a by 100b.

The area is 100a*100b=a*b*10,000=30*10,000=300,000 (square units)



Answer:  300,000 (square units)


8 0
3 years ago
A certain bacteria culture grows at a rate if 18% everday. There are currently 420 bacteria. How many bacteria will there be on
Anettt [7]

Answer:

1579

Step-by-step explanation:

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6 0
2 years ago
Can someone please help me with this math question .
Alona [7]

No, Yes, No, Yes

using the laws of exponents

(1)

(4^{3})³ = 4^{9}

4³ × 4³ = 4^{6}

4^{9} ≠ 4^{6} → No

(2)

(3^{4})^4 = 3^{16}

3^{8} × 3^{8} = 3^{16} → Yes

(3)

18^{8} = (6 × 3 )^8 = 6^{8} × 3^{8} ≠ 6^{4} × 3^{4} → No

(4)

20^{3} = (4 × 5 )³ = 4³ × 5³ → Yes




5 0
3 years ago
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