Answer:
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Step-by-step explanation:
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divide the total weight by the number of piles
9/5 = 1.8 pounds per pile
We will investigate how to determine Hamilton paths and circuits
Hamilton path: A path that connect each vertex/point once without repetition of a point/vertex. However, the starting and ending point/vertex can be different.
Hamilton circuit: A path that connect each vertex/point once without repetition of a point/vertex. However, the starting and ending point/vertex must be the same!
As the starting point we can choose any of the points. We will choose point ( F ) and trace a path as follows:

The above path covers all the vertices/points with the starting and ending point/vertex to be ( F ). Such a path is called a Hamilton circuit per definition.
We will choose a different point now. Lets choose ( E ) as our starting point and trace the path as follows:

The above path covers all the vertices/points with the starting and ending point/vertex are different with be ( E ) and ( C ), respectively. Such a path is called a Hamilton path per definition.
One more thing to note is that all Hamilton circuits can be converted into a Hamilton path like follows:

The above path is a hamilton path that can be formed from the Hamilton circuit example.
But its not necessary for all Hamilton paths to form a Hamilton circuit! Unfortunately, this is not the case in the network given. Every point is in a closed loop i.e there is no loose end/vertex that is not connected by any other vertex.
Factor x^5 - x to get x(x^4 - 1) = x(x^2-1)(x^2+1) = x(x-1)(x+1)(x^2+1)
We see that x = 0, x = 1 and x = -1 are the real number roots or x intercepts. Ignore the complex or imaginary roots. Unfortunately, the graph shows the x intercepts as -2, 0 and 2 which don't match up.
So there's no way that the given graph matches with f(x) = x^5-x.
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As more proof, let's consider the end behavior.
As x gets really large toward positive infinity, x^5 will do the same and so will x^5-x. Overall, f(x) will head off to positive infinity. Visually, moving to the right will have the graph move upward forever. This is the complete opposite of what is shown on the graph.
Likewise, the left endpoint should be aimed down instead of up. This is because x^5-x will approach negative infinity as x heads to the left.
In short, the graph shows a "rises to the left, falls to the right" end behavior. It should show a "falls to the left, rises to the right" pattern if we wanted to have a chance at matching it with x^5-x. Keep in mind that matching end behavior isn't enough to get a 100% match; however, having this contradictory end behavior is proof we can rule out a match.
I recommend using Desmos, GeoGebra, or whatever graphing program you prefer to plot out y = x^5-x. You'll get a bettter idea of what's happening.