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elixir [45]
2 years ago
14

Find the rate of change

Mathematics
1 answer:
Arte-miy333 [17]2 years ago
7 0

Answer:

2

Step-by-step explanation:

the rate of change is Rise/ Run

= Δy / Δx

= (y2 – y1) / (x2 – x1)

= (1 - (-1))/(-1 - (-2))

=2/1

=2

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Use the distributive for dx(8+6)
kramer
That would be 14 then.
8 0
2 years ago
What is the equivalent of 1/50 : fraction , in decimal form
lina2011 [118]
What is the equivalent of 1/50: fraction , in decimal form? We can determine the equivalent values of the fraction 1/50 in one simple way.
By dividing 1 and 50 to get the quotient of the digits given. <span><span>

1.  </span>1 / 50 = 0.02</span>

Therefore, 0.02 is the decimal form of the given fraction 1/50 and is a rational number.



8 0
3 years ago
Read 2 more answers
What is the quadratic regression equation for the data set? ​ ​ ​ <br><br> PLEASEE HELP ME
Soloha48 [4]
You're trying to find constants a_0,a_1,a_2 such that \hat y=a_0+a_1\hat x+a_2{\hat x}^2. Equivalently, you're looking for the least-square solution to the following matrix equation.


\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}

To solve \mathbf{Ax}=\mathbf b, multiply both sides by the transpose of \mathbf A, which introduces an invertible square matrix on the LHS.

\mathbf{Ax}=\mathbf b\implies\mathbf A^\top\mathbf{Ax}=\mathbf A^\top\mathbf b\implies\mathbf x=(\mathbf A^\top\mathbf A)^{-1}\mathbf A^\top\mathbf b

Computing this, you'd find that

\mathbf x=\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}\approx\begin{bmatrix}121.119\\-3.786\\-0.175\end{bmatrix}

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8 0
3 years ago
Please help me with this problem
diamong [38]
20%

(300-250)/250=0.2
8 0
3 years ago
The equation x+53=15 can be solved by performing two operations on both sides.
Wewaii [24]
Hey!


You're right! This equation can definitely be solved by performing two operations on both sides. Let me show you how it's done.

First, let's write out our equation.

<span><em>Original Equation :</em>
</span>x + 53 = 15

Now that that's done, we'll be performing two operations on both sides. The operation we'll want to do is subtracting both sides of the equation by 53. We do this to get x on its own.

<em>Original Equation :</em>
x + 53 = 15

<em>New Equation {Added Subtract 53 to Both Sides} :</em>
x + 53 - 53 = 15 - 53

Now we have to solve the equation. Let's do the left side first.

<em>Left Side of the Equation :</em>
x + 53 - 53 

<em>Left Side of the Equation {Solved} :</em>
x

Now, we'll solve the right side of the equation.

<em>Right Side of the Equation :</em>
15 - 53

<em>Right Side of the Equation {Solved} :</em>
-38

Now we can put both solutions to both sides of the equation together.

<em>New Equation :</em>
x = -38

Since this cannot be simplified any farther, this is our final answer. And that's it!

<em>So, now we know that in the equation x + 53 = 15,</em>  x = -38

Hope this helps!


- Lindsey Frazier ♥
3 0
3 years ago
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