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3 years ago

Simplify by expressing with radicals 3 + sqrt3 = ?

Mathematics

2 answers:

drek231 [11]3 years ago

7 0

Answer:

4.73205080757

Step-by-step explanation:

Korvikt [17]3 years ago

7 0

Answer:

3 + $\sqrt{3}$ = 4.73205

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Which quadrant will (30,-45) fall into?

Varvara68 [4.7K]

Answer:

Quadrant 4

Step-by-step explanation:

The x value is positive so it is either in 1 or 4

The y value is negative so it is either 3 or 4

To meet both conditions, it must be 4

6 0

2 years ago

Read 2 more answers

Solve for 2a:<br> a + 6 = 3a + 2<br> 2a

rosijanka [135]

Answer:

Break down the problem into these 2 equations.

a+6=3a+2

a+6=2a

Solve the 1st equation: a+6=3a+2a+6=3a+2.

a=2

Solve the 2nd equation: a+6=2aa+6=2a.

a=6

Collect all solutions.

a=2,6

Step-by-step explanation:

6 0

3 years ago

John is skiing on a mountain with an altitude of 1200 feet. The angle of depression is 21 About how far does

Agata [3.3K]

Answer:

John ski down the mountain is 1285.37 feet.

Step-by-step explanation:

Given : John is skiing on a mountain with an altitude of 1200 feet. The angle of depression is 21.

To find : About how far does John ski down the mountain ?

Solution :

We draw a rough image of the question for easier understanding.

Refer the attached figure below.

According to question,

Let AB be the height of mountain i.e. AB=1200 feet

The angle of depression is 21 i.e. $\theta=21^\circ$

We have to find how far does John ski down the mountain i.e. AC = ?

Using trigonometric,

$\cos\theta = \frac{AB}{AC}$

$\cos(21)= \frac{1200}{AC}$

$AC=\frac{1200}{\cos(21)}$

$AC=1285.37$

Therefore, John ski down the mountain is 1285.37 feet.

7 0

3 years ago

Find a point-slope form for the equation of the line satisfying the conditions.

natulia [17]

Answer:

y-5=3/7(x-3)

Step-by-step explanation:

the 3/7 is a fraction

6 0

3 years ago

Read 2 more answers

The equation of a line is y=-2x+1. What is the equation of the line that is parallel to the first line and passes through (2,2)?

Murrr4er [49]

Answer:

The equation in slope-intercept form is y=-2x+6.

The equation in standard form is 2x+y=6.

The equation in point-slope form is y-2=-2(x-2).

Step-by-step explanation:

The slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.

Parallel lines will have the same slope and different y-intercept.

Anyways the slope of y=-2x+1 is -2.

So the equation of our line we are looking for is -2.

So we know our equation is in the form y=-2x+b.

We must inf b using y=-2x+b with (x,y)=(2,2).

y=-2x +b with (x,y)=(2,2)

2=-2(2)+b

2=-4+b

Add 4 on both sides:

2+4=b

Simplify:

6=b

The equation is y=-2x+6.

Now it didn't say what form it wanted.

There are some forms I can give you like standard and point-slope form.

There is also general form but it is not too much different from standard form.

Standard form is ax+by=c where a,b, and c are integers if possible.

Point-slope form is y-y1=m(x-x1) where (x1,y1) is a point on the line and m is the slope.

So let's go for standard form (ax+by=c) first:

y=-2x+6

add 2x on both sides:

2x+y=6

This is standard form because it is in the form

ax+by=c.

Ok we know point (2,2) is on our line and we also know we have slope,m, is -2.

Point-slope form is

y-y1=m(x-x1)

y-2=-2(x-2)

8 0

3 years ago