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neonofarm [45]
3 years ago
9

Which answer does not correctly describe the graph of y = 5x + 12?

Mathematics
1 answer:
Ganezh [65]3 years ago
6 0
The answer for this question is c
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Find the amount financed and the finance charge in dollars for the following problem. Choose the correct answers.
diamong [38]

$350 * 30/100 = $ 105 which is down payment.

$350 - $105 = $245 which is left.

But he will pay $24.50 * 12 = $294 instead.

$294 - $245 = $49

He will pay $49 more.

He paid $105 as down payment and will pay $294 more with 12 months.

Total will be $105 + $294 = $399

4 0
3 years ago
You estimate the distance from your house to your school to be 1.6 miles. The actual distance is 1.9 miles. Find the percent err
Bezzdna [24]
To find percent error you use the following formula:
% Error =  \frac{final value - given value}{given value}
% error = (1.6 - 1.9)/1.9 * 100% = 15.79%
5 0
3 years ago
Find the sum. 2/5 + 1/2​
dybincka [34]
2/5 + 1/2

4+5 / 10 • look for the LCD of 5 and 2
which is 10 then 5 goes 2
times into 10 the multiply by 2
= 4. Then 2 goes 5 times into
10 then multiply by 1 = 5.

Therefore the sum of 2/5 + 1/2 =9/10
5 0
3 years ago
Read 2 more answers
Four int variables, x1, x2, y1, and y2, have been declared and been given values. write an expression whose value is the differe
Katen [24]
Even though we are using variables, we still know that "difference" means subtraction. So, if the larger is x1 and x2, those variables go first. The smaller, y1 and y2 will go second. So our problem will look like this:

(x1 <  x2 ? x2 : x1) - (y1 < y2 ? y1 : y2)
7 0
3 years ago
if in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99%
Dahasolnce [82]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The lifetime (in hours) of a 60-watt light bulb is a random variable that has a Normal distribution with σ = 30 hours. A random sample of 25 bulbs put on test produced a sample mean lifetime of = 1038 hours.

If in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99% confidence, how many randomly selected 60-watt light bulbs should be tested to achieve this result?

Given Information:

standard deviation = σ = 30 hours

confidence level = 99%

Margin of error = 6 hours

Required Information:

sample size = n = ?

Answer:

sample size = n ≈ 165

Step-by-step explanation:

We know that margin of error is given by

Margin of error = z*(σ/√n)

Where z is the corresponding confidence level score, σ is the standard deviation and n is the sample size

√n = z*σ/Margin of error

squaring both sides

n = (z*σ/Margin of error)²

For 99% confidence level the z-score is 2.576

n = (2.576*30/6)²

n = 164.73

since number of bulbs cannot be in fraction so rounding off yields

n ≈ 165

Therefore, a sample size of 165 bulbs is needed to ensure a margin of error not greater than 6 hours.

3 0
3 years ago
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