Which answer does not correctly describe the graph of y = 5x + 12?

Simplify. 4−16÷4+42 −16 13 15 16 PLEASE HELP

jok3333 [9.3K]

PEMDAS. 16/4 = 4. 4+42 = 46. 46-4 = 42. Answer is 42!

3 0

3 years ago

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1!+2(2!)+3(3!)+...+n(n!)=(n+1)!-1

anyanavicka [17]

Step-by-step explanation:

OK, let's assume it this way:

Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!

Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!=(2.1!-1!)+(3.2!-2!)+(4.3!-3!)+...+((n-1)n!-n!)=(2!-1!)+(3!-2!)+(4!-3!)+

Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!=(2.1!-1!)+(3.2!-2!)+(4.3!-3!)+...+((n-1)n!-n!)=(2!-1!)+(3!-2!)+(4!-3!)+...+(n+1)!-n!=(n+1)!-1!=(n+1)!-1

and boom problem solved

7 0

2 years ago

What is the equation of the line that passes through (-9,12) and is perpendicular to the line whose equation is y=1/3x 6?

tigry1 [53]

Y = 1/3x ? 6....slope here is 1/3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular line will have a slope of -3 (see how I flipped 1/3 and changed the sign)

y = mx + b
slope(m) = -3
(-9,12)...x = -9 and y = 12
now we sub and find b, the y int
12 = -3(-9) + b
12 = 27 + b
12 - 27 = b
-15 = b

so ur perpendicular equation is : y = -3x - 15

6 0

3 years ago

What are the roots of the quadratic function in the graph?

k0ka [10]

The answer would be B) -5, 3. The roots can be found where the graph crosses the x-axis, which on this graph is -5 and 3.

7 0

3 years ago

In a right triangle, the hypotenuse has endpoints P(–3, 2) and Q(1, –3).

allsm [11]

52, i am so sorry this is probably incorrect

4 0

3 years ago

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