The value of cosB ≅ 0.447 to three decimal places.
Since angle A and angle B are acute and tanB = 2, we find cosB from the trigonometric identity
tan²B + 1 = sec²B
<h3 /><h3>Find SecB</h3>
So, substituting the value of tanB into the equation, we have
tan²B + 1 = sec²B
2² + 1 = sec²B
4 + 1 = sec²B
5 = sec²B
Taking square root of both sides, we have
√sec²B = ±√5
secB = ±√5
<h3>
</h3><h3>
Find CosB</h3>
Since secB = 1/cosB, we have that
1/cosB = ±√5
⇒cosB = ±1/√5
Since B is acute, cosB will be positive.
So, cosB = 1/√5
cosB = 1/2.2361
cosB = 0.4472
cosB ≅ 0.447 to three decimal places.
So, the value of cosB ≅ 0.447 to three decimal places.
Learn more about cosine here:
brainly.com/question/10417664
Ok so,,,, first you find the area of a trapezoid which is b1 plus b2 times h over 2 so it is 9 plus 7 times 6 divided by two then you get 48 and you subtract by 20 times 24 bc its the area of rectangle so 480 minus 48 which is 432 cm squared
Answer:
The answer final
x1= -5; x2=9
Step-by-step explanation:
If you want me to expand on the equation leave me a comment :)
Answer:
y=-2x+1
Step-by-step explanation: