1)the mean of a, b, c, d, and e is 86. The mean of a, b, and c is 80 What is the mean of d and e?
1 answer:
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The percentage of animal wasted is the number of animal wasted over 100
85.7% of the wild caught animals are wasted
<h3>How to calculate the animal wasted</h3>From the question, we have:
Animals caught = 6 pounds
Salmon = 1 pound
The total weight in the system is:
Total = 6 pounds + 1 pound
So, we have:
Total = 7 pounds
The percent of wild caught animals wasted is then calculated as:
Simplify
Hence, 85.7% of the wild caught animals are wasted
Read more about percentage at:
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032
