Answer:the second one
Step-by-step explanation:
y1= log 3 etc so it the second one
Answer:
No, They will do it in more than an hour
t=1,1 h
Step-by-step explanation:
Vh=1mile/12min, Vt=1mile/15min They will meet to same time th=tt
sh=x, st=10-x, so V=s/t we have Vh=sh/t ; Vt=st/t ; t=(sh/Vh) = (st/Vt);
; so 
: if Vh=sh/t then 
Note: V=s/t : but in this case are 12 min (t) per mile (s), so 
Answer:
Explanation:
<u>1. Number of sequences with exactly seven heads:</u>
- First head can go in 9 different positions
- Second head can go in 8 different positions
- Third head can go in 7 different positions
- Fourth head can go in 6 different positions
- Fifth head can go in 5 different positions
- Sixth head can go in 4 different positions
- Seventh head can go in 3 different positions
That gives: 9×8×7×6×5×4×3
Since all the heads are equivalent, you have repetitions that are not different. Then, you must discount the combinations that are equivalent.
In how many ways seven heads can be arranged? 7×6×5×4×3×2×1
Then, you must divide 9×8×7×6×5×4×3 by 7×6×5×4×3×2×1.
- That is: 9 × 8 / 2 = 36 different ways of tossing seven heads
<u>2. Number of sequences with exactly eight heads:</u>
Following the same reasoning:
- 9×8×7×6×5×4×3×2 divided by 8×7×6×5×4×3×2×1 = 9
- That is 9 different ways of tossing eight heads.
<u>3. Number of sequences with exactly nine heads</u>
That is only one way: when all the tosses are heads: 1
<u>4. Number of sequences with at least seven heads</u>
Add the combinations of having exactly seven heads, eight heads and nine heads:
-ab + 4a + 3 - (-8ab + 6)......distribute the - thru the parenthesis
-ab + 4a + 3 + 8ab - 6.....now just combine like terms
7ab + 4a - 3 <===
