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3 years ago

3x-2y= 10 Write the slope intercept for of the equation

Mathematics

2 answers:

Savatey [412]3 years ago

3 0

Answer: y = -3/2x + 5

Step-by-step explanation:

Masja [62]3 years ago

3 0

Answer:

y= 3/2x - 5

Step-by-step explanation:

Slope intercept form is y=mx + b

1. subtract 3x from both sides -2y= -3x + 10

2. divide -2 on each value y= 3/2x - 5

3. simplify if needed (already in simplest form)

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State if the given functions are inverses NO LINKS!!!! Part 1

Dafna11 [192]

Step-by-step explanation:

h(x)=(-3x-15)/5

let y=(-3x-15)/5

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3 years ago

Read 2 more answers

Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?

likoan [24]

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=15,\:\quad a_n=2$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}$

$-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3$

$\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5$

$=\left(x+3\right)\left(2x^2-11x+5\right)$

$Factor: 2x^2-11x+5$

$2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)$

$=x\left(2x-1\right)-5\left(2x-1\right)$

$2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)$

$\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:}$

thus zeros of f(x) is

$x=-3,\:x=5,\:x=\frac{1}{2}$

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3 years ago

Read 2 more answers

Which of the following lines will have a negative slope? Select all that apply

olganol [36]

Answer:

1, 5

Step-by-step explanation:

-16/4=-4

10/5=2

1/2=1/2

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-1/4/1/2=-1/2

The negative ones are your answer.

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2 years ago