Answer:
72 pi + 48 pi= 120pi (not sure if I am right tho)
Step-by-step explanation:
The Pyth. Thm. applies here:
(√x + 1)^2 + (2√x)^2 = (2√x + 1 )^2
Expanding the squares:
x + 2sqrt(x) + 1 + 4x = 4x + 4sqrt(x) + 1
Let's subtract x + 2sqrt(x) + 1 + 4x from both sides:
4x + 4sqrt(x) + 1
-(x + 2sqrt(x) + 1 + 4x)
-------------------------------
3x + 2sqrt(x) - 4x = 0
Then 2sqrt(x) = x
Squaring both sides, 4x = x^2, or x^2 - 4x = 0. Then (x-4)x = 0, and the two possible solutions are 0 and 4.
Check these results by substitution. Does the Pyth. Thm. hold true for x=4?
What are ya sayin
Step-by-step explanation:
I think it is D ...........
It depends. For example the GCF of 4 &2 is 4, so in a sense yes. With other numbers (such as odds) that is not always the case :D
