First you multiply the last term by the first term (3h+16h+15). Then find numbers that add to 16 and multiply to 15 then add or subtract it from (3h+15)(3h+1). Then factor if possible (h+5)(3h+1)
Answer:
7.
Step-by-step explanation:
21 = 3 * 7
28 = 2 * 2 * 7
42 = 2 * 3 * 7
Collecting common factors:
t is common to all 3 sets of factors so
HCF = 7.
An aritmetic sequence is like this

where a1=first term and d=common difference
geometric is

where a1=first term and r=common ratio
can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same
therfor we need to solve

what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?
when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal
the answer is no, a sequence cannot be both aritmetic and geometric
Question is not complete and so I have attached the complete question.
Answer:
C: f(x) = -½x + 4
Step-by-step explanation:
Using slope formula between 2 points, we know that;
slope; m = (y2 - y1)/(x2 - x1)
Let's consider 2 points from the table;
(0, 4) and (-4, 6)
Thus;
m = (6 - 4)/(-4 - 0)
m = 2/-4
m = -½
Now using slope intercept form equation which is y - y1 = m(x - x1), we can find the equation of the function by picking on point say (0, 4).
Thus;
y - 4 = -½(x - 0)
y - 4 = -½x
y = -½x + 4
Thus;
f(x) = -½x + 4