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3 years ago

I need help. For khan academy. Explain if you can

Mathematics

1 answer:

olga55 [171]3 years ago

3 0

Answer: Ok so the number on the y axis is 0,-3 cause it is above -4. And the next point is 1,-5. That is because the first thing you plot is the x axis and then the y axis so that it gives you your number

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a meteor train in Delhi carried 4865 passengers in 16 trips.Each trip had an equal number is passengers how many passengers trav

Musya8 [376]

Answer:

304

Step-by-step explanation:

4865/16 = 304.0625 or about 304

I have to round it since you can't bring part of a student in a trip lol.

<em>Ace Carlos</em>

7 0

3 years ago

What is the quadratic regression equation for the data set?

Svet_ta [14]

Answer:

y=−0.004x2+0.415x−0.546

6 0

3 years ago

Solve for x & y. 30x−42y=−6 and 5x−7y=−1

vladimir1956 [14]

Um.. Both of those equations are the exact same. Divide both sides of the first equation by 6. You get:

$\frac{30x - 42y}{6} = \frac{-6}{6} \\ 5x - 7y = -1$

That is the exact same as the second equation. This system has an infinite number of solutions. 5x - 7y = -1 is a line, so basically every point on that line is a solution to the system.

For example, $x = 0$ and $y = \frac{1}{7}$ would work, but so would $x = 1$ and $y = \frac{6}{7}$

4 0

3 years ago

Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr

Bad White [126]

Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

$x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}$

Where the determinant is D = b^2 - 4*a*c.

Now, if D>0

we have the square root of a positive number, which will be equal to a real number.

√D = R

then the solutions are:

$x = \frac{-b +- R }{2*a}$

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

$x = \frac{-b +- C*i }{2*a}$

We have two complex solutions.

If D = 0

√0 = 0

then:

$x = \frac{-b +- 0}{2*a} = \frac{-b}{2a}$

We have only one real solution (or two equal solutions, depending on how you see it)

3 0

3 years ago

Alex scored 98,72, and 87 on his first three math test. What must he score on the next test to have an average of at least 86 (P

ss7ja [257]

Answer:

$\huge\boxed{\text{At least an } 87\%}$

Step-by-step explanation:

In order to find what score Alex must earn to have an average of 86 on all his tests, we need to first note what the formula to find the average of a data set is.

$\displaystyle \frac{x_1+x_2+...x_n}{n}$