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3 years ago

Find the inverse of y=3(x+1)^2

Mathematics

1 answer:

Semmy [17]3 years ago

6 0

Answer:

Step-by-step explanation:

y=3(x+1)²

note : y ≥ 0 because : 3(x+1)² ≥ 0

calculate x : (x+1)² = y/3

x + 1 = √(y/3) or x + 1 = - √(y/3)

x = -1 + √(y/3) or x = - 1 - √(y/3)

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7x - 20 = 2x - 3(3x + 2)

kirill [66]

Answer:

7x-20=2x-3(3x+2)

We move all terms to the left:

7x-20-(2x-3(3x+2))=0

We calculate terms in parentheses: -(2x-3(3x+2)), so:

2x-3(3x+2)

We multiply parentheses

2x-9x-6

We add all the numbers together, and all the variables

-7x-6

Back to the equation:

-(-7x-6)

We get rid of parentheses

7x+7x+6-20=0

We add all the numbers together, and all the variables

14x-14=0

We move all terms containing x to the left, all other terms to the right

14x=14

x=14/14

x=1

Step-by-step explanation:

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