To begin, Arnold should sort on whether or not it is a screw, nut, bolt.
This might only be # 1 and 3 but you should be able to put together a number line with the information I provided. Some of the #s may look different but that is because I used the Least Common Denominator. Hope this helps!
Screws: Least to greatest (top = least)
4 Screws 4/64” x 3” long
12 Screws 5/64” x 3” long
3 Screws 6/64” x 4” long
6 Screws 11/64” x 4” long
16 Screws 24/64” x 2” long
1 Screw 28/64” x 3” long
1 Screw 32/64” x 3” long
1 Screw 48/64” x 2” long
Hex Bolts: Least to greatest by diameter (top = least)
4 Hex bolts 1.5” x 4” long
4 Hex bolts 1.875” x 4” long
1 Hex bolt 2.25” x 2” long
6 Hex bolts 3.375” x 3” long
4 Hex bolts 3.75” x 3” long
When we see
has only 1 soulution
because its range is [0,π]
so only one solution exist at π/2
Answer:
<u>The lines are:</u>
and
Since after multiplying by -3 the equations sum to 0, the equations are same.
Same equations produce overlapping lines, hence you can see one line only.
