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Ksju [112]
3 years ago
12

A circle is divided into 6 equal parts. what is the total angle measure of 1 part?

Mathematics
1 answer:
Rus_ich [418]3 years ago
7 0

Answer:

dis \: is \: easy \\ angle \: in \: a \: circle = 360 \\ the \: angle \: is \: divided \: into \: six \: part \\ divide \: the \: 360 \: by \: 6 \\  \frac{360}{6}  = 60 \\ therefore \: the \: angle \: of \: one \: part \: \\  = 60 \: degree

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(-3)3 (26)
Lemur [1.5K]

<em><u>Question:</u></em>

Geoffrey is evaluating the expression (-3)^3(2^6)/(-3)^5(2^2) as shown below.

(-3)^3(2^6)/(-3)^5(2^2) = (2)^a/(-3)^b = c/d

What are the values of a, b, c, and d?

<em><u>Answer:</u></em>

<em><u>The values are a = 4, b = 2, c = 16, d = 9</u></em>

<em><u>Solution:</u></em>

Given that,

Geoffrey is evaluating the expression

\frac{(-3)^3 \times 2^6}{(-3)^5 \times 2^2}

He is evaluating as shown below:

\frac{(-3)^3 \times 2^6}{(-3)^5 \times 2^2} = \frac{2^a}{-3^b} = \frac{c}{d}

From given,

\frac{(-3)^3 \times 2^6}{(-3)^5 \times 2^2}

Use the law of exponent

\frac{a^m}{a^n} = a^{m - n}

Therefore,

\frac{(-3)^3 \times 2^6}{(-3)^5 \times 2^2} = \frac{2^{6-2}}{(-3)^{5-3}}\\\\Simplify\\\\\frac{(-3)^3 \times 2^6}{(-3)^5 \times 2^2} = \frac{2^4}{-3^2}

Thus,

a = 4

b = 2

Simplify further

\frac{(-3)^3 \times 2^6}{(-3)^5 \times 2^2} = \frac{2^4}{-3^2} = \frac{16}{9}

Thus,

c = 16

d = 9

Thus values are a = 4, b = 2, c = 16, d = 9

8 0
4 years ago
I need help with this
baherus [9]

Answer:

0.4

Step-by-step explanation:

drawing a triangle with each side correspondent to each of its measurements all you are doing is dividing the side that you would want to find its scale factor of, which in this case you would take AB and DE and have AB/DE dividing that and getting 0.4 as its scale factor.

6 0
3 years ago
What is 3(4-x)-5x=52
Rainbow [258]

Answer:

x= -5

I hope this is the right answer. :)

5 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
3 years ago
What is 17 2/3÷5 =(the awnser)​
Travka [436]

Answer:

3 \frac{8}{15}

8 0
3 years ago
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