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ipn [44]
3 years ago
11

A cosmetics company makes three batches of a nail polish color called Purple Dusk using the recipe shown.

Mathematics
1 answer:
Ivanshal [37]3 years ago
3 0

Answer:

Batch 1:- Red 2  ounces     Blue 1 1/2 ounces

Batch 2:-  Red 3     White  3 3/4 ounces.

Batch 3:- White  4 1/6      Blue  2 1/2 ounces.

Step-by-step explanation:

Batch 1

Amount of the white paint = 5/12 of the batch = 2 1/2  or 5/2 ounces.

5/12 is equivalent to 5/2 ounces of white paint.

1/12   ......................... 5/2 / 5 =  5/10 = 1/2 ounce.

Red paint.

!/3 of the product contains red paint which is 4/12 so this is 4 times 1/12 = 4 * 1/2 ounce   = 2 ounces of red paint.

Blue paint.

Similarly to the above amount of blue paint =  1/4 =3/12

= 3 * 1/2 = 1 1/2 ounces of  blue paint.

Batch 2.

We can calculate the missing quantities in a similar way to Batch 1.

Blue Paint =  3/12 of the product  = 2 1/4 ( = 9/4) ounces  so

1 /12 =

9/4 * 1/3 =  9/12 = 3/4 ounce

Red Paint:-  1/12 is equivalent to 3/4 ounce so

Amount of red paint = 4 * 3/4 = 3 ounces  (answer)

White paint = 5 * 3/4 =  15/4 = 3 3/4 ounces (answer)

Batch 3.

Red paint = 3 1/3 ounces is equivalent to  4/12 of the product.

So 1/12 = 10/3  / 4 = 10/12 = 5/6 ounces.

White paint = 5/6 * 5 = 4 1/6 ounces.

Blue paint = 5/6 * 3 = 15/6 = 2 1/2  ounces.




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vova2212 [387]
<h2>Answer:</h2>

The answer is 16.

<h2>Step-by-step explanation:</h2>

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Let's see this!

An easy way to complete the square if you have the constants for x2 and

But not the non-variable number is to divide the x constant, and then square it.

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\frac{8x}{2} \\\\4^2=16\\

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2 years ago
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2 years ago
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kramer

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Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa
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Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation  

n=580 represent the random sample taken    

X represent the seafood sold in the country that is mislabeled or misidentified by the people

\hat p=0.25 estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

\alpha=0.01 represent the significance level (no given, but is assumed)    

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204

0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

Part c

A government spokesperson claimed that the sample size was too​ small, relative to the billions of pieces of seafood sold each​ year, to generalize. Is this criticism​ valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

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