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stich3 [128]
3 years ago
12

A dumpling machine automatically inserts mixed vegetables and meat filled wontons into a plastic package. Past experience reveal

ed that some packages were underweight and some were overweight, but most of them had satisfactory weight.
Weight % of Total
Underweight 2.5
Satisfactory 90.0
Overweight 7.5

Required:
What is the probability of selecting two packages that are satisfactory?

a. 0.900
b. 0.729
c. 0.810
d. 0.075
Mathematics
1 answer:
Tanya [424]3 years ago
6 0

Answer:

c. 0.810

Step-by-step explanation:

Given, total % of satisfactory packages = 90% = 0.90

Now, since selecting a satisfactory package is independent of any other trials (i.e. all the selection trials are independent to each other)

Hence, Probability of selecting two packages that re satisfactory

P(Selecting 2 satisfactory packages) = (0.90)^2

P(Selecting 2 satisfactory packages) = 0.90*0.90

P(Selecting 2 satisfactory packages) = 0.810

Note: We are selecting product since the chance of selecting in each trials are independent.

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never [62]
<h3>1 Answer: v = -130</h3>

=============================================================

Explanation:

Because we're given multiple choices to pick from, we can go through each to do trial and error.

For instance, if v = 52, then

v/13 < -7

52/13 < -7

4 < -7

but that's a false statement since 4 is not smaller than -7. Use a number line to see this. You should have -7 to the left of 4, showing that -7 is the smaller value.

Because 4 < -7 is false, this means v/13 < -7 is false when v = 52. This rules out v = 52. You should find that v = 26 and v = -39 won't work for similar reasons.

Only v = -130 works since...

v/13 < -7

-130/13 < -7

-10 < -7

This is true because -10 is to the left of -7 on the number line.

-------------------------------------------------

Another approach:

We have some unknown number v, and we're dividing by 13 to get the expression v/13. To undo this, we multiply both sides by 13

v/13 < -7

13*(v/13) < 13*(-7) .... multiply both sides by 13

v < -91

So any solution to the original inequality must be smaller than -91. This allows us to rule out v = 52, v = 26 and v = -39.

The value v = -130 is smaller than -91, so it satisfies v < -91. Therefore, v = -130 is a solution to the original inequality.

6 0
3 years ago
What are the solutions to x^2-5x+3=0?
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Answer:

Step-by-step explanation:

You need to use the quadratic equation

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Givens

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x = \frac{5 +/- \sqrt{5^2 - 4a*1*3} }{2} \\

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Answer:

The answer if B. Hope this helps.

Step-by-step explanation:

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djverab [1.8K]
Hi there

Replace the blank space by x

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I hope that's help ! 

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