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allsm [11]
3 years ago
6

Which of the following is not a solution of (x-3)(2x+1)(3x-2)=0?

Mathematics
1 answer:
kramer3 years ago
3 0

Answer:

The answer is option D.

5/3

Hope this helps you

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A triangle has a base of (3x + 7) and a height of (5x - 1). A second
Mars2501 [29]

Answer:

The difference between the area of the original triangle and the area of the new triangle is \Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1).

Step-by-step explanation:

The equation for the area of a triangle (A_{\bigtriangleup}) is:

A_{\bigtriangleup} = \frac{1}{2}\cdot b \cdot h

Where:

b - Base, dimensionless.

h - Height, dimensionless.

The expression for each triangle are described below:

First Triangle (b = 3\cdot x + 7, h = 5\cdot x - 1)

A_{\bigtriangleup,1} = \frac{1}{2}\cdot (3\cdot x+7)\cdot (5\cdot x -1)

Second Triangle (b = 3\cdot (3\cdot x+7), h = 2\cdot (5\cdot x -1))

A_{\bigtriangleup,2} = 3\cdot (3\cdot x+7)\cdot (5\cdot x -1)

The difference between the area of the original triangle and the area of the new triangle is:

\Delta A_{\bigtriangleup} = A_{\bigtriangleup,2}-A_{\bigtriangleup,1}

\Delta A_{\bigtriangleup} = 3\cdot (3\cdot x+7)\cdot (5\cdot x-1)-\frac{1}{2} \cdot (3\cdot x+7)\cdot (5\cdot x-1)

\Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1)

The difference between the area of the original triangle and the area of the new triangle is \Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1).

7 0
3 years ago
1 2 3
Ira Lisetskai [31]
128 I think is the answer
8 0
3 years ago
80 percent of a number is x what is 100 percent of that number
Mariana [72]

I don't know exactly what you're asking but 80% of 100 is 80

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=t%20%3D%20%20%5Cfrac%7Bm%20%2B%201%7D%7B%20%5Csqrt%7Bm%20-%201%7D%20%7D%20" id="TexFormula1" t
dangina [55]

Answer:

Step-by-step explanation:

Abcdefghijklmnopqrstuvwxyz

3 0
3 years ago
I need help!!!
Kruka [31]

Answer: x = -3/4 can not be a rational zero of the polynomial.

Step-by-step explanation:

We have the polynomial:

6x^5 + ax^3 -bx -12 = 0.

The theorem says that:

If P(x) is a polynomial with integer coefficients, and p/q is a zero of P(x) then p is a factor of the constant term (in this case the constant term is -12) and q is a factor of the leading coefficient (in this case the leading coefficient is 6.).

The factors of -12  (different than itself) are (independent of the sign).

1, 2, 3, 4 and 6.

So p can be: 1, -1, 2, -2, 3, -3, 4, -4, 6, -6.

The factors of 6 are:

1, 2 and 3, so q can be 1, -1, 2, -2, 3, -3.

Then the option that can not be a zero of the polynomial is

x = -3/4

because the number in the denominator must be a factor of the leading coefficient, and 4 is not a factor of six.

4 0
4 years ago
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