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Lilit [14]
3 years ago
11

Arionna needed to graph triangle PQR reflected across the y-axis. Her work is shown below. Arionna’s Work: Blue right-arrow red.

P (3,7) right arrow P prime (3, negative 7). Q (0, 4) right-arrow Q prime (0, 4). R (5, 8) right-arrow R prime (negative 5, 8). Arionna’s Graph On a coordinate plane, a red triangle has points (negative 7, 3), (negative 5, 8), (0, 4). A blue triangle has points (0, 4), (3, 7), (5, 8). Which statements identify her errors? Check all that apply. Arionna did not find the correct point for P’. She should have negated the x-value, not the y-value. Arionna did not find the correct value for Q’. All points in a reflection will move. Arionna did not find the correct value for R’. She should have negated the y-value, not the x-value. Arionna’s red triangle should be reflected below the horizontal axis rather than across the vertical axis. Arionna switched the order of the coordinates of P’ (3, –7) when she graphed them.
Mathematics
2 answers:
Andrej [43]3 years ago
7 0

Answer:

A,c,b

Step-by-step explanation:

laiz [17]3 years ago
7 0

Answer:

A and E

Step-by-step explanation:

...

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Answer:

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2 years ago
The difference between the square roots of a number is 30. What is the number?
Vilka [71]
The difference between the square roots of a number 30 is 15 I am pretty sure it is 15
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3 years ago
If the length of each side of an equilateral triangle were increased by 50 percent, what would be the percent increase in the ar
Shkiper50 [21]

Answer:

<u><em>The area increase by 225%</em></u>

<em><u>Step-by-step explanation: </u></em>

<em><u>attachment of a triangle</u></em>

<em><u>The area of a triangle equilateral is calculated with the next formula:</u></em>

<em><u>A=\frac{a*h}{2}</u></em>

<em><u>h^{2} +(\frac{a}{2})^{2}=a^{2}</u></em>

<em><u>h^{2} = a^{2} - \frac{a^{2} }{4}= \frac{a^{2} }{4}*3</u></em>

<em><u>h=\sqrt{\frac{a^{2}*3 }{4} }</u></em>

<em><u>h=\frac{\sqrt{3}*a }{2}</u></em>

<em><u>replacing in the A equation:</u></em>

<em><u>A=\frac{a*\sqrt{3}*a }{2*2}</u></em>

<em><u>A=\frac{\sqrt{3}*a^{2} }{4}</u></em>

<em><u>Now each side increse by 50% ⇒ a=1.5a</u></em>

<em><u>A= \frac{\sqrt{3}*(1.5a)^{2} }{4}</u></em>

<em><u>A=\frac{\sqrt{3}*a^{2}* 2.25 }{4}</u></em>

<em><u>A=2.25 * \frac{\sqrt{3}*a^{2} }{4}</u></em>

<em><u>It means that the area incrase by 225%</u></em>

6 0
3 years ago
Diego deposited \$ 10,000$10,000 for 44 years at a rate of 6\%6% simple interest. ​Find the amount of interest Diego earned afte
timama [110]

Answer:

$2,400

Step-by-step explanation:

Note: The correct years is 4 not 44

The Principal  = $10,000

Time period = 4 years

Rate = 6 % p.a.

Simple Interest = Principal * Rate * Time

Simple Interest = $10,000 * 6% * 44

Simple Interest = $2,400

So, the amount of interest Diego earned after four years is $2,400

8 0
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I need help with 1-3 i don’t understand that problems and its already over due
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Step-by-step explanation:

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t = -2 / (2 × -0.5)

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0 = -0.04x (x − 22)

x = 22

The maximum width is 22 feet.

7 0
3 years ago
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