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2 years ago

(-5,-3) (5,5) slope What is the slope ?

Mathematics

2 answers:

Setler [38]2 years ago

6 0

Answer:

The slope is 10/8

Step-by-step explanation:

You would rise 10 units and you would run 8 units.

Ira Lisetskai [31]2 years ago

4 0

What is the slope?-44

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When is the measure of a base angle

Vlada [557]

Elaborate this question

8 0

2 years ago

Find the discount on a note for $23,000 made by Jacques on February 10 to be repaid on August 10 of the same year with a discoun

Olenka [21]

Total Value =$23,000

Time = 10 february to 10 august = 6 months

And

Rate of discount = 9% =0.09

Now we have to find the discount on the note

So we multiply the amount , time and rate

but time should be in years

So 6 months = 6/12 years = 0.5 years

Discount = 23,000 * 0.5 * 0.09 = 1035

Hence total Discount = $1035

3 0

3 years ago

Read 2 more answers

2. Find the LCM of the following numbers by division method. (a) 16 and 28 (b) 36 and 44 (c) 45 and 120 (d) 10, 15 and 30 (e) 52

kati45 [8]

<h2> Answer </h2>

(a):112

(b):396

(c):360

(d):30

(e):1664

(f):240

<h2 />

3 0

1 year ago

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

kherson [118]

Answer:

The answer is

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

Step-by-step explanation:

Remember that Taylor says that

$f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }$

For this case

$f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18$

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

5 0

2 years ago

Simplify the expression

erastova [34]

Answer : A

We need to simplify the given expression

Lets factor numerator first

$2x^2-5x-3$ =(2x+1)(x-3)

$x^2+8x+15$ =(x+5)(x+3)

Now we factor the denominator

$x^2+x-20$ =(x+5)(x-4)

$2x^2+9x+4$ =(2x+1)(x-4)

Now we simplify it

$\frac{(2x+1)(x-3)}{(x+5)(x-4)} * \frac{(x+5)(x+3)}{(2x+1)(x-4)}$

Now cancel out same factors. so we left with

$\frac{(x+3)(x-3)}{(x+4)(x-4)} }$

Now multiply the factors

$\frac{x^2-9}{x^2-16} }$

6 0

2 years ago