Given:
Monthly fees for the local pool are $8 per month and $2 per visit.
Hector pays $34 in pool fees total for the month.
To find:
The number of times he visit the pool.
Solution:
We have,
Monthly fee of pool = $8
Additional fee = $2 per visit
Let Hector visit x times.
Additional fee for x times = $2x
Total fee = Monthly fee + Additional fee



Divide both sides by 2.


Therefore, Hector visit the pool 13 times.
6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1
6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)
6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)
6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²
Answer:
The correct answer is t < 60.
Step-by-step explanation:
Lauren wants to keep her cell phone bill below $60 per month.
Lauren's current cellphone plan charges her a fixed price of $30 and per text price for one text is $0.50.
Let Lauren sends t texts in a complete month.
Total money spent on texts in a month is given by $ (0.50 × t)
Therefore Lauren's total spent in a month is given by $ (30 + (0.50 × t)).
But this amount should be under $60 as per as the given problem.
∴ 30 + (0.50 × t) < 60
⇒ (0.50 × t) < 30
⇒ t < 
⇒ t < 60.
So in order to keep her phone monthly bill under $60, Lauren should keep her number of texts below 60.
Answer:
The answer to your question is below
Step-by-step explanation:
1) Given
2) Subtraction property of equality (because we are subtracting the same quantity on both sides).
3) Simplification
4) Subtraction property of equality ( because we are subtracting the same quantity on both sides).
5) Simplification
6) Multiplication property of equality (because we are multiplying the same quantity on both sides).
7) Simplification
Answer:
base = 8
Step-by-step explanation:
The general formula for the area of a parallelogram is:
A = bh, where b = the length of the base and h = the height
Using the given values for area and height, we can solve for the missing variable of 'b':
23
2

Multiply both sides by the reciprocal:


